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4 years ago

Write the equation for the graph below. PLEASE I NEED HELP !

Mathematics

1 answer:

mrs_skeptik [129]4 years ago

5 0

Y= 1x+ 3
1x is the slope and 3 is the y intercept
I did rise over run to find the slope 3/3=1
Y is 3 because y intercept is when a line go through the y axis and it’s on 3
hope this helps!

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

Weather forecasters use a barometer to measure

Zepler [3.9K]

Answer: air pressure

Whenever you hear things like "high pressure" or "low pressure" on weather reports, they measured the pressure using a barometer. Knowing the air pressure helps determine if there is a higher chance of rain or storms for instance.

Typically but not always, high pressure correlates to sunny days and dry weather. Low pressure often brings about rain. This is of course a very oversimplified viewpoint.

4 0

2 years ago

What is the average of 3.28+6.90+5.30+12.00+4.77

schepotkina [342]

The answer should be 32.25

6 0

3 years ago

What is the difference?

Leokris [45]

11/18 is the correct answer:))

6 0

2 years ago

Read 2 more answers

Help with number three!

natka813 [3]

1 hour and 35 minutes without the break. 60 minutes in an hour, subtract 15 from 50 = 35 minutes. It starts at 3 and ends at 4, which is 1 hour apart. Because there us a break you subtract 30 from the minutes , 35-30=5. So you have 1 hour and 5 minutes.

7 0

3 years ago