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Luba_88 [7]
3 years ago
15

What's the difference between partial variation and direct variation​

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

<u>Direct Variation is a relation that is of the form y = mx.</u>

and

<u>Partial Variation is a relation that is of the form y=mx+b</u>

Explanation:

This is a simple way to see the difference between them.

<em>Hope This help you!</em>

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B is the answer due to when finding the solution you have to equalize the problems and solve.
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12) A bag contains four red marbles and eight
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Answer: 8/12%   6/11%

Step-by-step explanation: so 4 red marbles and 8 blue marbles so in total that's 12 marbles so if you have 8 blue marbles you have a 3/4 chance of getting blue but only 1/4 chance of red

So 5 green marbles and 6 yellow marbles so in total that's 11 marbles so if you have 6 yellow marbles you have a 3/4 chance of getting yellow but only 1/4 chance of green

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Are Euler circuits also Euler paths
Neko [114]

Answer:

An Euler circuit is a circuit that uses every edge of a graph exactly once. An Euler circuit starts and ends at the same vertex.

Step-by-step explanation:

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3 years ago
What is the volume of the triangular prism?
Rasek [7]

Answer:

The answer is 480 cubic inches

Step-by-step explanation:

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3 0
3 years ago
The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. The area of
borishaifa [10]

Answer: the equations are

y × x = 750 - - - - - - - -- - -1

x = y - 5 - - - - - - - - - - - 2

y^2 - 5y - 750 = 0 is used to solve for y

Step-by-step explanation:

The area of a rectangular room is 750 square feet. The rectangular room has dimensions for length, y and width, x.

Area of the rectangular room = length, y × width, w. Therefore, from the information given above about the area,

y × x = 750

xy = 750 - - - - - - - -- - -1

The width of the room is 5 feet less than the length of the room. This means

x = y - 5 - - - - - - - - - - - 2

Equation 1 and equation 2 above can be used to solve for the length as well as the width of the room.

We can go further to find the length by substituting equation 2 into equation 1.

The equation becomes

y(y-5) = 750

y^2 -5y = 750

y^2 - 5y - 750 = 0

This equation is used to solve for y

4 0
3 years ago
Read 2 more answers
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