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4 years ago

How do u solve 2x3/5+1/5

Mathematics

1 answer:

Sergeeva-Olga [200]4 years ago

7 0

Answer:

1 2/5

Step-by-step explanation:

The answer to the above question is 1 2/5

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14 is 10% of ____?<br> Or what is 14 10% of

leonid [27]

Answer:

THE ANSWER TO THE TOP LINE IS: 140

Step-by-step explanation:

why? becuase 10 times 10 is 100 all whole fractions need to be ?/100 (something over 100) so then becuase you did 10 times ten to find what 14 is you do 14 times 10. it should look like this :D.

10*10=100

14*10=140 . 140/100 is your answer or 140 :)

3 0

2 years ago

Which equation represents the line that passes through the points (4, 6) and (−2, −1)?

KatRina [158]

Find the slope first by using rise/run

$m=\frac{6-(-1)}{4-(-2)}\\m=\frac{6+1}{4+2}\\m=\frac{7}{6}$

$y=mx+b\\y=\frac{7}{6}x+b$

We need to find the y-intercept. Substituting one of given ordered pairs. I will use (-2,-1).

Substitute x = -2 and y = -1 in the equation.

$-1=\frac{7}{6}(-2)+b\\-1=\frac{7}{-3}+b\\-1=-\frac{7}{3}+b\\-1+\frac{7}{3}=b\\b=\frac{4}{3}$

Thus the y-intercept is 4/3.

From y = mx+b, the equation is.

$y=\frac{7}{6}x+\frac{4}{3}$

8 0

3 years ago

A craftsman can sell 10 jewelry sets for $500 each. He knows

liraira [26]

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning $=\text{Price of each set}\times \text{no of set}$

Earning $=(500-25n)(10+n)$

$E=5000+500n-25n^2-250n$

differentiate to get the maximum value

$\frac{dE}{dn}=-50n+250$

Equate $\frac{dE}{dn}$ to get maximum value

$-50n+250=0$

$n=\frac{250}{50}$

$n=5$

Thus must sell 5 extra set to maximize its earnings.

5 0

3 years ago

Compare Elena's and Noah's money using fraction

Leokris [45]

Um did you get the wrong picture?

4 0

3 years ago

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The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation.

podryga [215]

Rate of change refers to moving a certain amount of distance over a certain time period
rate of change= velocity in this case.

7 0

3 years ago

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