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ohaa [14]
4 years ago
5

How do u solve 2x3/5+1/5

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
7 0

Answer:

1 2/5

Step-by-step explanation:

The answer to the above question is 1 2/5

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SinA=√1-x÷√1+X<br> Find the value of cosA
Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = \sqrt{1} - x

Hypotenuse = \sqrt{1} + x

Let's find the adjacent side using the Pythagorean theroem

(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2

1 + x^2 = 1 - x^2 + x^2

x = \sqrt{\frac{1 + x^2}{1 -x^2} }

cos A = x/hypotenuse

cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

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6 0
2 years ago
Graph the piecewise function given below. i need help please
yawa3891 [41]

Answer:

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8 0
3 years ago
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Find the value of b if the following figures are similar.​
chubhunter [2.5K]

Answer:

7

Step-by-step explanation:

20 - 12 = 8

15 - b = 8

-b = 8 - 15

b = 7 ( -ve signs will become +ve)

3 0
3 years ago
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Find the distance between the pair of points.
SVEN [57.7K]

Answer:

Distance is \sqrt{290} units

Step-by-step explanation:

Use the distance formula which is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2)

We are given that (x_1,y_1) is (-6,-23) and (x_2,y_2) is (-23,-24), therefore the distance between the two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}

d=\sqrt{(-23+6))^2+(-24+23))^2}

d=\sqrt{(-17)^2+(-1)^2}

d=\sqrt{289+1}

d=\sqrt{290}

Therefore, the distance between (-6,-23) and (-23,-24) is \sqrt{290} units.

3 0
3 years ago
Translate the sentence into an inequality.
viktelen [127]

The appropriate inequality would be 4x + 19 ≤ -26

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3 years ago
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