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Alexxx [7]
2 years ago
14

Convert 330 litres per hour into millilitres per minute (ml/min).

Mathematics
1 answer:
VMariaS [17]2 years ago
6 0
1 litre = 1000 milliliters
1he= 60 min
330 x 1000/60
5500 milliliters/ second
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7 0
3 years ago
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PLEASE HURRY IM GIVING BRAINLIEST AND 50 POINTS!!! for the function g(x) = x - 2x^2, find g(-3) + 13
Inessa [10]

Hey there! I'm happy to help!

If we have g(-3) we plug -3 into our function as x.

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g Use the information below for questions 1 through 5. A San Francisco-based tech firm is able to keep 80% of its new employees
meriva

Answer:

0.64 = 64% probability that two randomly sampled new employees will both be able to survive their first year

Step-by-step explanation:

For each employee, there are only two possible outcomes. Either they survive the first year, or they do not. The probability of an employee surviving the first year is independent of other employees. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A San Francisco-based tech firm is able to keep 80% of its new employees after one year.

This means that p = 0.8

Q1. What is the chance that two randomly sampled new employees will both be able to survive their first year

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.8)^{2}.(0.2)^{0} = 0.64

0.64 = 64% probability that two randomly sampled new employees will both be able to survive their first year

3 0
3 years ago
Which statement below is not a valid part of this proof?
DiKsa [7]
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8 0
3 years ago
Add. write the doubles fact you used to solve the problem. 4+5=9
boyakko [2]
4+5=9 4+4=8+1=9 I hope this helps! Follow me
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