Find the midpoint.<br> (2,-4) & (-6,-8)

Flaws in concrete beams follow a Poisson process. Beams fabricated by process A have flaw rates of 10/meter while beams fabricat

Kay [80]

Answer:

P(A | Y = 8) = 0.633

Step-by-step explanation:

It is really a simple and interesting question, as it involves the Poisson distribution and probability.

First of all, let's try to understand the problem statement clearly. It says that there are two process by which beams are made, namely A and B.

It further states that, beam made by process A has = 10 flaws per meter.

Beam made by process B has = 5 flaws per meter.

Finally, it says that from a yard containing equal numbers of process A and process B beans, one beam is randomly selected and 1 - meter of it is inspected. And they have found 8 flaws in it.

We now, have to find out the probability that the inspected beam is from process A.

For this,

Let's suppose, Y is no. of flaws

So,

P (Y=8|A) = $\frac{e^{-10}. 10^{8} }{8!}$

where , e = Euler's Constant = 2.71828

P (Y=8|A) = 0.11

Similarly for process B

P (Y=8|B) = $\frac{e^{-5}. 5^{8} }{8!}$

P (Y=8|B) = 0.06

As, we know from the problem statement that there are equal numbers of process A and process B beams.

So, the probability of A = Probability of B = 0.5

P(A) = 0.5

P(B) = 0.5

We need to find, P(A|Y=8) and for this we need to find the P(Y=8) first.

Using the law of total probability:

P(Y=8) = P(Y = 8 |A) P(A) + P(Y = 8|B) P(B)

Plug in the values:

P(Y=8) = (0.11 x 0.5) + (0.06 x 0.5)

P(Y=8) = 0.088

Now, by applying Bayes Theorem, we can find the required probability:

P(A | Y = 8) = P(Y = 8 | A) P(A) / P(Y = 8)

8 flaws are found, the probability the inspected beam was fabricated using process A is :

P(A | Y = 8) = 0.11 x 0.5 / 0.088

P(A | Y = 8) = 0.633

Furthermore,

8 flaws are found, the probability the inspected beam was fabricated using process B is :

P(B | Y = 8) = 1-P(A | Y = 8)

P(B | Y = 8) = 1 - 0.633

P(B | Y = 8) = 0.367

5 0

3 years ago

3k - 5 = 20k what is k

Usimov [2.4K]

K is whatever you want it to be

5 0

3 years ago

Factor the following expression x^2+5x+6

Olegator [25]

Answer:

(x + 2) (x + 3)

Step-by-step explanation:

x² + 5x + 6

x² + 3x + 2x +6

7 0

3 years ago

In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de

Naily [24]

Answer:

$z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318$

$p_v =P(Z>0.318)=0.375$

So the p value is a very high value and using the significance level provided $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation

$X_{1}=507$ represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

$n_{1}=32601$ sample elected from arizona

$\hat p_{1}=\frac{507}{32601} =0.0156$ represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

$p_{2}=\frac{1}{88}= 0.0114$ represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in the nation

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{507+1}{32601 +88}=0.01554$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318$

Statistical decision

The significance level provided is $\alpha=0.01$ , and we can calculate the p value for this test.

Since is a one right sided test the p value would be:

$p_v =P(Z>0.318)=0.375$

So the p value is a very high value and using the significance level provided $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

5 0

3 years ago

What is the volume of the following composite shape ? Plz help will mark u brainliest!!!

sergeinik [125]

Answer:

150

Step-by-step explanation:

6 0

4 years ago

Find the midpoint. (2,-4) & (-6,-8)