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snow_lady [41]
3 years ago
14

HELP ASAP!

Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer:

Both Kurt and Maria are right, because 3,585 should be rounded up to 3,600, and 21% of this amount can be approximated by either finding 10% of 3,600 and multiplying the result by 2 or by finding 1/5 of 3,600.

Step-by-step explanation:

Umnica [9.8K]3 years ago
3 0

D. Both Kurt and Maria are right, because 3,585 should be rounded up to 3,600, and 21% of this amount can be approximated by either finding 10% of 3,600 and multiplying the result by 2 or by finding 1/5 of 3,600.

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a speeding ticket cost $94.50 plus $2 for every mile over the speed limit. BRANDY ticket cost her 112.50. how many miles over th
Novosadov [1.4K]
She drove 9 miles over the speed limit.

94.50 + 2m = 112.50
Subtract 94.50 from both sides

2m = 18
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m = 9
7 0
3 years ago
Read 2 more answers
Complete the equivalent fractions: 3/ = 15/20= /100
Genrish500 [490]
Your answer would be 3/4 = 15/20 = 75/100
Now their are two ways to figure out this problem. 
You can look at the relationship with 3 and 15. 3 x 5 is 15 so you can determine that something x 5 equals 20. Well 20 x 5 = 4 so your answer is 3/4.
You would then do the same thing with 15/20.
20 x 5= 100, so do 15 x 5 which is 75. Answer is 75/100
Now here is the 2nd way you could have done it.
well we know that 3/4 equals .75 and that equals 75/100 as a fraction. Then divide top and bottom by 5 to get 15/20.
5 0
3 years ago
Please help me thanks please
leonid [27]
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3 0
3 years ago
Help binomial distributions
Ymorist [56]

We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is


P(\text{k successed on n trials}) = \binom{n}{k}p^k(1-p)^{n-k}


Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.


We can compute their probability and sum them:\binom{5}{3}\left(\frac{3}{7}\right)^3\left(\frac{4}{7}\right)^2 + \binom{5}{4}\left(\frac{3}{7}\right)^4\left(\frac{4}{7}\right)^1 + \binom{5}{5}\left(\frac{3}{7}\right)^5 \approx 0.36788


So, the answer is about 36.79%

3 0
3 years ago
What is 2,767,545 rounded to the nearest tenth?
solmaris [256]

2,767,550 is the answer

5 0
3 years ago
Read 2 more answers
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