3 years ago

What is the area of a triangle whose vertices are J(−2, 1) , K(4, 3) , and L(−2, −5) ?

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

3 0

Answer:

the area of the triangles vertices would be 25.13

Step-by-step explanation:

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pishuonlain [190]

We know that
[LA]=pi*r*l
where
LA is the lateral area of the cone
r is the radius
l is the slant height
l=LA/(pi*r)
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the answer is
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X^2 + 35x - 450
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