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Alinara [238K]
3 years ago
13

Please factor these three questions- (30 points)

Mathematics
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

(a - 6)²

(3c + 1)²

30e(e - 1)²

Step-by-step explanation:

a^2-12a+36

a² - 6a - 6a + 36

a(a - 6) - 6(a - 6)

(a - 6)(a - 6)

(a - 6)²

9c^2 + 6c + 1

9c² + 3c + 3c + 1

3c(3c + 1) + 1(3c + 1)

(3c + 1)(3c + 1)

(3c + 1)²

30e^3 - 60e^2 + 30e

30e(e² - 2e + 1)

30e(e² - e - e + 1)

30e[e(e - 1) - (e - 1)]

30e(e - 1)(e - 1)

30e(e - 1)²

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Simplify<br>6^7/6^5<br>leaving your answer in index form.​
Juli2301 [7.4K]

Answer:

Step-by-step explanation: the and is 36.

8 0
3 years ago
2. Armand is planning a crawfish boil for the weekend. Crawfish are like tiny lobsters, about 3 to 4 in. long. They are especial
vivado [14]

Hi there!

Here's the important information we know:

10 lbs of crawfish → 24 oz of seasoning


a) To answer the question in a, you will need to use the cross product method:

10 lbs of crawfish → 24 oz of seasoning

1 lbs of crawfish → X oz of seasoning


24 ÷ 10 = X oz of seasoning

2.4 = X oz of seasoning


Answer a) : This means that 1 lb of crawfish requires 2.4 oz of seasoning.


b) We now know that for 1 lb of crawfish you need 2.4 oz of seasoning, so in order to know how much seasoning you need for 30 lbs of crawfish, you need to multiply 2.4 by 30 :

2.4 × 30 = 72


Answer b): You would need 72 oz of seasoning for 30 lbs of crawfish.


c) We know that for 1 lb of crawfish you need 2.4 oz of seasoning, so in order to know the maximum number of pounds of crawfish that can be cooked with 36 oz of seasoning, you need to divide 36 by 2.4 :

36 ÷ 2.4 = 15


Answer c): You can cook a maximum of 15 pounds of crawfish with 36 oz of seasoning.


There you go! I really hope this helped, if there's anything just let me know! :)

6 0
3 years ago
I need help on exponets
atroni [7]

Answer:

i so exponets are numbers that can go into anything

Step-by-step explanation:

i just told you

6 0
4 years ago
6) use the steps to solve this system of equations. Show your work.<br><br> Y=x+2 Y=x^2-4
zepelin [54]

y= x + 2 and  y = x^2 - 4

Substitute mx + b for y

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x^2 - 4 = x + 2

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Substitute the first x value  into the linear equation and solve for y

y = 3 + 2

y = 5

One solution is (3, 5)

Substitute the second x value into the  linear equation and solve for y

y = -2 + 2

y = 0

Another solution is (-2 , 0)

7 0
3 years ago
324x+ 3234= 4343<br><br> anyone bor ed? i have a free day and ldk what 2 do
lina2011 [118]

Answer:

x=3.42

Step-by-step explain:

hope it works

3 0
3 years ago
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