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Yuliya22 [10]
3 years ago
10

Simplify6^7/6^5leaving your answer in index form.​

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

Step-by-step explanation: the and is 36.

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At a local fitness​ center, members pay a ​$10 membership fee and ​$5 for each aerobics class. Nonmembers pay ​$6 for each aerob
sveta [45]
One way to solve it is writing two equations based on the info so

y = 5x + 10 for members
y = 6x for nonmembers

(the + 10 isn't included in the second equation because nonmembers won't pay a membership fee)

and to find their intersection point (where the values will be the same), you just set them equal to each other:

5x + 10 = 6x

subtract 5x

x = 10 classes
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Convert 86 degrees Fahrenheit to degrees celsius
dybincka [34]
86 degrees Fahrenheit is 30 degrees Celsius 
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Given f(x)=x^2+4x+7 .
ivolga24 [154]
The correct answer for this question is A. 
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3 years ago
John has two colored varieties of water bottles: white water bottles and black water bottles. The total number of water bottles
mixas84 [53]

Answer:

15 black water bottles

Step-by-step explanation:

let w represent white water bottles, and let b represent black water bottles.

set up a system of equations:

w+b=20

w+2b=35

(the top equation shows that the number of white water bottles he sold and the number of black water bottles he sold equals to 20, since it says that the total number of water bottles is 20. the bottom equation shows that white water bottles cost $1, and black water bottles cost $2, and that the total amount of money he got from selling them is $35).

in the top equation, isolate w:

w+b=20

w=20-b

now we do substitution. in the bottom equation, substitute 20-b for w:

w+2b=35

20-b+2b=35

then, solve:

b+20=35

b=15

this means that he sold 15 black water bottles.

4 0
3 years ago
In the figure above, the vertices of square
Olin [163]

(C) 6 + 3√3

<u>Explanation:</u>

Area of the square = 3

a X a = 3

a² = 3

a = √3

Therefore, QR, RS, SP, PQ = √3

ΔBAC ≅ ΔBQR

Therefore,

\frac{BQ}{BA} = \frac{QR}{AC}

\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

BQ = √3

So, BQ, QR, BR = √3 (equilateral triangle)

Let AP and SC be a

So, AQ and RC will be 2a

In ΔAPQ,

(AP)² + (QP)² = (AQ)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

So, AP and SC = 1

and AQ and RC = 2 X 1 = 2

Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR

Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3

Perimeter = 6 + 3√3

Therefore, the perimeter of the triangle is 6 + 3√3

8 0
3 years ago
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