Because the group of small cells would have a greater surface area-to-volume ratio, so they are able to exchange materials with their surroundings more efficiently.
Answer: 4/16 yellow Labradors, 9/16 black Labradors and 3/16 brown Labradors.
Explanation: Two dihybrids would have BbEe alleles. Using Mendel's chess table of independent segregation to show the offspring, we have the following results:
BBee - 1/16 - yellow
BBEe - 2/16 - black
BBEE - 1/16 - black
BbEe - 4/16 - black
Bbee - 2/16 - yellow
BbEE - 2/16 - black
bbEe - 2/16 - brown
bbEE - 1/16 - brown
bbee - 1/16 - yellow
If the offspring presents B_E_ phenotypes, it will have black pigment deposition. If the offspring presents bbE_ phenotypes, it will have brown pigment deposition. Otherwise, if it presents _ _ee phenotypes, there won't be any pigment deposition, therefore they are yellow.
Adding up all the phenotypes ratios, we have <u>4/16 yellow Labradors, 9/16 black Labradors and 3/16 brown Labradors</u>.
If you were to remove the decomposers all of the dead plants and animals on the ground floor would remain there and cause a build up of dead animals and plant matter not being removed via the decomposers
3 is enzymes, 7 is c, 6 is either c or d, 5 is B, 4 is c
