From my research on the internet, the image attached supports this problem. The two lines are parallel, as supported by the converse of corresponding angles postulate. It states that:<span> If a </span>transversal<span> intersects two lines and the corresponding angles are </span>congruent<span>, then the lines are parallel.</span>
I’m doing this so I can ask a question
Answer:
C(C^3 + 8C^2 -3C -7)
Step-by-step explanation:
(-3C^4-5C^2-7C)+(4C^4+8C^3+2C^2)
(-3C^4 +4C^4)+8C^3 + ( -5C^2 +2C^2) -7C [Combine like terms]
C^4 + 8C^3 -3C^2 -7C [Simplify]
C(C^3 + 8C^2 -3C -7) [Isolate 1C from the rest]
Answer: he lived 9 months in Portugal and 5 months in Brazil.
Step-by-step explanation:
Let x represent the number of months he lived in Portugal.
Let y represent the number of months he lived in Brazil.
Wolfrich lived in Portugal and Brazil for a total period of 14 months in order to learn Portuguese. This means that
x + y = 14
He learned an average of 130 new words per month when he lived in Portugal and an average of 150 new words per month when he lived in Brazil. In total, he learned 1920 new words. This means that
130x + 150y = 1920- - - - - - - - - - - 1
Substituting x = 14 - y into equation 1, it becomes
130(14 - y) + 150y = 1920
1820 - 130y + 150y = 1920
- 130y + 150y = 1920 - 1820
20y = 100
y = 100/20
y = 5
x = 14 - y = 14 - 5
x = 9
