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MissTica
3 years ago
12

pearl will put wire around a rectangular lot with a width of 20m and a length that is two times its width.how many mters of wire

will she need?​
Mathematics
1 answer:
tangare [24]3 years ago
5 0

Let's see what to do buddy...

_________________________________

STEP (1)

First we need to find the length.

(( length is two times the width ))

Length = 20 × 2 = 40 m

_________________________________

STEP (2)

Pearl will put wire <em><u>around</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>rect</u></em><em><u>angular</u></em><em><u>.</u></em>

<em>Around</em><em> </em><em>of</em><em> </em><em>rectangular</em> = <em>Perimeter</em><em> </em><em>of</em><em> </em><em>it</em>

So we must to find the perimeter of the rectangular.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: p = 2(length + width) \\  \\ p = 2(20 + 40) \\  \\  \:  \:  \:  \: p = 2 \times 60 = 120

So Pearl needs <em>120 meters</em> of wire.

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

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