<span>a)
Z*_Upper = (76 - 62.7)/2.5 = 5.32
Z*_Lower = (57 - 62.7)/2.5 = -2.28
The requirement is to get p(-2.28 < Z < 5.32) = p(Z<5.32) - p(Z<-2.28).
Use normal distribution table to get the answer for p and multiply with 100 to get the percentage.
The other questions are now easy for you to answer on your own. Hope it helps.
</span>
Answer:
a) 19 students
b) the mean 3 9/19
the median 3
the mode 3
c) the range 6
Step-by-step explanation:
The data set shows that
0 points gets 1 student,
1 point gets 1 student,
2 points get 2 students,
3 points get 6 students,
4 points get 4 students,
5 points get 3 students and
6 points get 2 students.
a) There are 1+1+2+6+4+3+2=19 students.
b) The mean is
The average score is 3 9/19 points.
The median is 10th term in the data set - 3 points (means the middle score in the data set)
The mode is 3 points (means most happened score)
c) The range of the data is 6-0=6 points.
Answer:
Its Patrick
Step-by-step explanation:
I assume the sentences:
"23 employees speak German; 29 speak French; 33 speak Spanish"
mean these speak ONLY the respective languages other than English.
Then the calculations boil down to those who speak ONLY two languages, noting that 8 speak French, German and Spanish, which need to be subtracted from
1. French and Spanish: 43-8=35 (speak only two foreign languages)
2. German and French: 38-8=30 (speak only two foreign languages)
3. German and Spanish: 48-8=40 (speak only two foreign languages).
Now We add up the total number of employees:
zero foreign language = 7
one foreign language = 23+29+33=85
two foreign languages = 30+35+40=105
three foreign languages=8
Total =7+85+105+8=205
(a) Percentage of employees who speak at least one foreign lanugage = (85+105+8)/205=198/205=.966=96.6%
(b) Percentage of employees who speak at least two foreign lanugages = (105+8)/205=113/205=.551=55.1%
