P(at least 2 students have the same birthday)= 1- P(no 2 students have the same birthday)
Because P(A)=1-P(A'), where A is an event, and A' the complement of that event.
P(no 2 students have the same birthday)=
think of the problem as follows. We have an urn of balls, numbered from 1 to 365 (the number of the days of the year.
What is the probability of picking 56 different numbered balls, with replacements?
The first one can be any of the 365
the second any of 364 (since one selection has already been made)
the third any of the 363
.
.
and so on
the 56th selection is one of 310 left
Answer:
Answer:
-3.25
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
I am guessing you want the area of the parallelogram.
Take the longer side to be the base.
Area = base * distance between base and opposite side
= 26 * 12.5
= 325 cm^2.
There are zero positive real roots for the given polynomial equation 
. This is explained by Descarte's rule of signs. So, the best choice is T (true).
<h3>What is Descarte's rule of signs?</h3>
- Descarte's rule of signs tells about the number of positive real roots and negative real roots.
- The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
- The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.
<h3>Calculation:</h3>
The given polynomial equation is
On applying Descarte's rule of signs,
Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.
Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.
Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).
Learn more about Descarte's rule of signs here:
brainly.com/question/11590228
#SPJ1
