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lakkis [162]
3 years ago
5

HELPPPP !!! ILL GIVE U BRAINLIEST

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
I believe the answer is D because those equation indicate an area on the negative side
ahrayia [7]3 years ago
6 0
I agree I think the answer is d
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Assume that there are 56 students in this class. what is the probability that at least two students share a? birthday
navik [9.2K]

P(at least 2 students have the same birthday)= 1- P(no 2 students have the same birthday)

Because P(A)=1-P(A'), where A is an event, and A' the complement of that event.

P(no 2 students have the same birthday)=

\frac{365}{365}* \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*... \frac{310}{365}

think of the problem as follows. We have an urn of balls, numbered from 1 to 365 (the number of the days of the year. 

What is the probability of picking 56 different numbered balls, with replacements?

The first one can be any of the 365

the second any of 364 (since one selection has already been made)

the third any of the 363
.
.
and so on

the 56th selection is one of 310 left


Answer: 

\frac{365}{365}* \frac{364}{365}*\frac{363}{365}*\frac{362}{365}*... \frac{310}{365}


4 0
3 years ago
*2.6-(5.85)<br> Evaluate It
daser333 [38]

Answer:

-3.25

Step-by-step explanation:

4 0
3 years ago
PQRS is a parallelogram with PQ=26cm and QR=20cm . If the distance between the longer-sides is 12.5cm , Find​
Kay [80]

Answer:

Below.

Step-by-step explanation:

I am guessing you want the area of the parallelogram.

Take the longer side to be the base.

Area = base * distance between base and opposite side

=  26 * 12.5

= 325 cm^2.

6 0
3 years ago
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
a mountain climber ascends a mountain to its peak the peak is 12,740 ft above sea level the climber then descends 200ft to meet
Marizza181 [45]
He would be 12,540 ft above sea level
4 0
4 years ago
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