Plug in e for 3.
10(3+7)
Use the distributive property. a(b+c)= ab+ac
10*3= 30, 10*7=70
30+70=100
The expression equals 100.
I hope this helps!
~kaikers
Answer:
The third quartile is:
![Q_3=29](https://tex.z-dn.net/?f=Q_3%3D29)
Step-by-step explanation:
First organize the data from lowest to highest
4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44
Notice that we have a quantity of n = 20 data
Use the following formula to calculate the third quartile ![Q_3](https://tex.z-dn.net/?f=Q_3)
For a set of n data organized in the form:
![x_1, x_2, x_3, ..., x_n](https://tex.z-dn.net/?f=x_1%2C%20x_2%2C%20x_3%2C%20...%2C%20x_n)
The third quartile is
:
![Q_3=x_{\frac{3}{4}(n+1)}](https://tex.z-dn.net/?f=Q_3%3Dx_%7B%5Cfrac%7B3%7D%7B4%7D%28n%2B1%29%7D)
With n=20
![Q_3=x_{\frac{3}{4}(20+1)}](https://tex.z-dn.net/?f=Q_3%3Dx_%7B%5Cfrac%7B3%7D%7B4%7D%2820%2B1%29%7D)
![Q_3=x_{15.75}](https://tex.z-dn.net/?f=Q_3%3Dx_%7B15.75%7D)
The third quartile is between
and ![x_{16}=29](https://tex.z-dn.net/?f=x_%7B16%7D%3D29)
Then
![Q_3 =x_{15} + 0.75*(x_{16}- x_{15})](https://tex.z-dn.net/?f=Q_3%20%3Dx_%7B15%7D%20%2B%200.75%2A%28x_%7B16%7D-%20x_%7B15%7D%29)
![Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29](https://tex.z-dn.net/?f=Q_3%20%3D29%20%2B%200.75%2A%2829-%2029%29%5C%5C%5C%5CQ_3%20%3D29)
Answer:
19.35% probability that five will have completed four years of college
Step-by-step explanation:
For each individual chosen, there are only two possible outcomes. Either they have completed fourr years of college, or they have not. The probability of an adult completing four years of college is independent of any other adult. So the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
28% of individuals
This means that ![p = 0.25](https://tex.z-dn.net/?f=p%20%3D%200.25)
For a sample of 15 individuals, ages 25 and older, what is the probability that five will have completed four years of college?
This is P(X = 5) when n = 15. So
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 5) = C_{15,5}.(0.28)^{5}.(0.72)^{10} = 0.1935](https://tex.z-dn.net/?f=P%28X%20%3D%205%29%20%3D%20C_%7B15%2C5%7D.%280.28%29%5E%7B5%7D.%280.72%29%5E%7B10%7D%20%3D%200.1935)
19.35% probability that five will have completed four years of college
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
<h3>How many children went to the movie theatre?</h3>
In this question we have a <em>word</em> problem, whose information must be translated into <em>algebraic</em> expressions to find a solution. Let be x and y the number of children and adults that went to the movie theatre, respectively.
We need two <em>linear</em> equations, one for the number of people assisting to the theatre and another for the total sales:
x - 4 · y = 0 (1)
6.30 · x + 9.50 · y = 1063.20 (2)
By algebraic procedures the solution to this system is: x = 122.559, y = 30.639. Since the number of tickets sold are integers, then we truncate each result: x = 122, y = 30.
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
To learn on systems of linear equations: brainly.com/question/27664510
#SPJ1
Let x = the length of the shorter piece
x+x+16=50in
2x=50-16
2x=34
x=17
Then
x+16=17+16
x+16=33
Subtract 16 from both sides
The lengths are 17in and 33in