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2 years ago

The number of eggs e in the carton and the total costs t of the eggs. what is the dependent variable

Mathematics

1 answer:

just olya [345]2 years ago

6 0

T because you need to know the number of eggs, e, to know how much it costs.

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How do I solve this?

laila [671]

The < is just like and equal sign just looks a little different think of it that was for the first couple steps. So you have 13-3y<-5. First do, -5+13=8. Now you have -3y<8. Then your want to do 8 divided by -3 and you get=-2.666666667 and that equals y.

-2.7=y then make that equal sign into the normal sign again. -2.7

7 0

2 years ago

Read 2 more answers

A wise man once said "500 reduced by 3 times my age is 218." What is his age? The wise man is _______ years old.

GrogVix [38]

Answer:

Step-by-step explanation:

94444444444444444444444444

5 0

2 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

1 year ago

(HELP ASAP PLEASE)

vlada-n [284]

Answer:

for four copies the cost is $72

Step-by-step explanation:

52 + 5a = 24 + 12a

28 + 5a = 12a

28 = 7a

a = 4

52 + 20 = 72

for four copies the cost is $72

6 0

2 years ago

Maura drives to work, a distance of 30 miles in 40 minutes. she takes the same route to return home. if her average speed on the

Viefleur [7K]

Well to solve this firstly we should calculate her average speed while she was going to work. Which comes out to be 45 miles per hour.

Now if her average speed while going home is half as fast as while coming to work was, the answer would be 22.5 miles per hour. So the average speed for the total journey would be the average for these two values. As the distance was same for both the journeys we can simply do 45 + 22.5 / 2 = 33.75 mph.

8 0

2 years ago