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3 years ago

The number of eggs e in the carton and the total costs t of the eggs. what is the dependent variable

Mathematics

1 answer:

just olya [345]3 years ago

6 0

T because you need to know the number of eggs, e, to know how much it costs.

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Which statements are true? check all that apply

Sever21 [200]

That would be C, D, E and F.

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4 years ago

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Xby the power of 5 times y to the power of 6 over 2 by the power of -2 times xby the power of 0times x by the power of 9

mars1129 [50]

Answer:

We have the sentence:

"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"

Let's break it into parts.

"X by the power of 5 times y to the power of 6..."

This can be written as:

x^5*y^6

"... 2 by the power of -2 times x by the power of 0times x by the power of 9"

This can be written as:

2^(-2)*x^(0)*x^(9)

And we have the quotient between the first thing and the second thing, then the equation is:

$\frac{x^5*y^6}{2^{-2}*x^0*x^9}$

And any number by the power of 0 is equal to 1, then:

x^0 = 1, then we can rewrite the equation as:

$\frac{x^5*y^6}{2^{-2}*x^9}$

We can keep simplifying this.

We know that:

a^(-n) = (1/a)^(n)

Then:

2^(-2) = (1/2)^2 = 1/4

Then we get:

$\frac{x^5*y^6}{2^{-2}*x^9} = \frac{x^5*y^6}{x^9}*4$

And we also know that:

a^n/a^m = a^(n - m)

Then:

$\frac{x^5*y^6}{x^9}*4 = 4*y^6*\frac{x^5}{x^9} = 4*y^6*x^{5 - 9} = 4*y^6*x^{-4} = \frac{4*y^6}{x^4}$

And we can't simplify this anymore.

8 0

3 years ago

How do I get (tan^2(x)-sin^2(x))/tan(x) equal to (sin^2(x))/cot(x)

shepuryov [24]

$LHS\\ \\ =\frac { \tan ^{ 2 }{ x-\sin ^{ 2 }{ x } } }{ \tan { x } } \\ \\ =\frac { 1 }{ \tan { x } } \left( \tan ^{ 2 }{ x-\sin ^{ 2 }{ x } } \right)$

$\\ \\ =\frac { \cos { x } }{ \sin { x } } \left( \frac { \sin ^{ 2 }{ x } }{ \cos ^{ 2 }{ x } } -\frac { \sin ^{ 2 }{ x\cos ^{ 2 }{ x } } }{ \cos ^{ 2 }{ x } } \right) \\ \\ =\frac { \cos { x } }{ \sin { x } } \left( \frac { \sin ^{ 2 }{ x-\sin ^{ 2 }{ x\cos ^{ 2 }{ x } } } }{ \cos ^{ 2 }{ x } } \right)$

$\\ \\ =\frac { \cos { x } }{ \sin { x } } \cdot \frac { \sin ^{ 2 }{ x\left( 1-\cos ^{ 2 }{ x } \right) } }{ \cos ^{ 2 }{ x } } \\ \\ =\frac { \cos { x } }{ \sin { x } } \cdot \frac { \sin ^{ 2 }{ x\cdot \sin ^{ 2 }{ x } } }{ \cos ^{ 2 }{ x } } \\ \\ =\frac { \cos { x } \sin ^{ 4 }{ x } }{ \sin { x\cos ^{ 2 }{ x } } } \\ \\ =\frac { \sin ^{ 3 }{ x } }{ \cos { x } }$

$\\ \\ =\sin ^{ 2 }{ x } \cdot \frac { \sin { x } }{ \cos { x } } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \frac { \cos { x } }{ \sin { x } } } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \cot { x } } \\ \\ =\frac { \sin ^{ 2 }{ x } }{ \cot { x } } \\ \\ =RHS$

8 0

3 years ago

Mrs. Santos baked 25 cookies. 3 fifths of the cookies were oatmeal. How many oatmeal cookies did Mrs. Santos bake?

grigory [225]

Answer: 15 oatmeal cookies.

Step-by-step explanation:

There were 25 cookies baked.

Out of these, 3/5 are oatmeal cookies.

The amount of actual oatmeal cookies is:

= fraction of oatmeal cookies * total number of cookies

= 3/5 * 25

= 75 / 5

= 15 oatmeal cookies.

7 0

3 years ago

What is 4(3x  6y) equivalent to?

miss Akunina [59]

Answer:

2x/y ??

Step-by-step explanation:

4 0

3 years ago

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