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xz_007 [3.2K]
3 years ago
5

Find the distance between the points P and Q shown. Question 6 options: A. 73−−√ B. 13−−√ C. 5–√ D. 65−−√

Mathematics
2 answers:
alexdok [17]3 years ago
5 0

Answer:

d=\sqrt{73}

Step-by-step explanation:

Q(5, -1)

P(-3, 2)

<u>Using the distance formula</u>:

d=\sqrt{(x_{2}-x_{1})^2+(y_2+y_1)^2}

d=\sqrt{(-3-5)^2+(2-(-1))^2}

d=\sqrt{(-8)^2+(3)^2}

d=\sqrt{64+9}

d=\sqrt{64+9}

d=\sqrt{73}

d\approx 8.5

Ganezh [65]3 years ago
4 0
Answer is d = square root 73 bro
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Here is the work using polynomial long division:
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x - 6 | x² - 10x + 24
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ohaa [14]

Step-by-step explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;

=9 \times x\\= 9x

The quotient of that number and 5.

= \frac{x}{5}

The difference between both expression;

9x - \frac{x}{5}

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as 9x - \frac{x}{5}

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:

\frac{n}{12}

Eight more than the resulting function is;

\frac{n}{12}+8

Hence eight more than the quotient of twelve and a number n is expressed as \frac{n}{12}+8

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;

6-x

product of a number x and the quantity 'six minus the number is;

x(6-x)

quotient of eight and the number is;

\frac{8}{x}

Taking the resulting sum of the last two expression

x(6-x) + 8x

Hence the product of a number and the quantity 'six minus the number' plus the quotient of eight and the number is expressed as;

x(6-x) + 8x

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

The consecutive even numbers are gotten by adding 2 to the preceding number. The two consecutive even integers are 2x+2 and 2x+2+2

the sum of three consecutive even integers is expressed as;

= 2x +(2x+2)+(2x+2+2)\\=  2x+(2x+2)+(2x+4)

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3 years ago
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