What expressions equal to 19

100 POINTS FOR BOTH SIDES PLZZZ Plzzz help me with this SIDES

Oliga [24]

Answer:

Step-by-step explanation:

5.

point = (x, y)

A = ( $1\frac{1}{2}$ , 12)

B = ( $2\frac{1}{2}$ , 20)

C = (3, 24)

D = ( $3\frac{1}{2}$ , 28)

y/x ratios

$\frac{12}{1\frac{1}{2} }$

$\frac{20}{2\frac{1}{2} }$

24/3

$\frac{28}{3\frac{1}{2} }$

6.

(1 2/3, 3 1/3) = 3 1/3 ÷ 1 2/3 = 2

(1 1/4, 2 1/2) = 2 1/2 ÷ 1 1/4 = 2

(3, 7) = 7 ÷ 3 = 2 1/3

(4 1/2, 9) = 9 ÷ 4 1/2 = 2

The ratio 7/3 (x = 3 and y = 7) is not proportionally related to the others.

The other ratios are equal to each other and are therefore in proportion.

7. yes

5 0

1 year ago

7,707 ÷ 24 what does this Equal and what is the remainder?

DochEvi [55]

Answer:

321 R 3

Step-by-step explanation:

the quotient is 321 with a remainder of 3

you can check your work by doing 321 * 24 + 3 = 7,707

6 0

2 years ago

Read 2 more answers

How many of these pitchers can a cylinder with height 9 inches and 2r fill? Explain how you know.

irakobra [83]

Answer:

4 pitches

Step-by-step explanation:

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers can a cylinder with height 9 inches and radius 2r fill? explain how you know.

Solution:

The volume of a cylinder is given by:

V = πr²h;

where V is the volume, r is the radius of the cylinder and h is the height of the cylinder.

A cylinder with height 9 inches and radius r can fill a certain pitcher. Therefore the volume of the cylinder is:

V = πr²h = πr²(9) = 9πr²

V = volume of pitcher = volume of cylinder with radius r = 9πr²

For a cylinder with height 9 inches and radius 2r its volume is:

V2 = πr²h = π(2r)²(9) = 36πr²

Therefore, the number of pitchers a cylinder with height 9 inches and radius 2r can fill is:

number of pitches = 36πr² / 9πr² = 4

Therefore a cylinder with height 9 inches and radius 2r can fill 4 pitches.

3 0

2 years ago

A tank is filled at a constant rate. 10 minutes after filling is started, the tank contains 4.8L of water. After 35 minutes the

Mashcka [7]

Answer:

Part A)

0.1 liters per minute.

Part B)

There was initially 3.8 liters of water.

$\displaystyle V(t) = 0.1(t - 10) + 4.8$

Part C)

562 minutes.

Step-by-step explanation:

A tank is filled at a constant rate. After 10 minutes, the tank contains 4.8 L of water and after 35 minutes, the tank contains 7.3 L of water.

Part A)

We can represent the current data with two points: (10, 4.8) and (35, 7.3). The x-coordinate is measured in minutes since the tank began to be filled and the y-coordinate is measured in how full the tank is in liters.

To find the rate at which the tank is being filled, find the slope between the two points:

$\displaystyle m = \frac{\Delta y}{\Delta x} = \frac{(7.3)-(4.8)}{(35)-(10)} = \frac{2.5}{25} = 0.1$

In other words, the rate at which the tank is being filled is 0.1 liters per minute.

Part B)

To find the function of the volume of the tank, we can use the point-slope form to first find its equation:

$\displaystyle y - y_1 = m( x - x_1)$

Where m is the slope/rate of change and (x₁, y₁) is a point.

We will substitute 0.1 for m and let (10, 4.8) be the point. Hence:

$\displaystyle y - (4.8) = 0.1(x - 10)$

Simplify:

$\displaystyle y = 0.1(x-10) + 4.8$

Since y represent how full the tank is and x represent the time in minutes since the tank began to be filled, we can substitute y for V(t) and x for t. Thus, our function is:

$\displaystyle V(t) = 0.1(t - 10) + 4.8$

The initial volume is when t = 0. Evaluate:

$\displaystyle V(0) = 0.1 ((0) - 10) + 4.8 = 3.8$

There was initially 3.8 liters of water.

Part C)

To find how long it will take for the tank to be completely filled given its maximum capacity of 60 liters, we can let V(t) = 60 and solve for t. Hence:

$60 = 0.1(t - 10) + 4.8$