Distance (km)

En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand

Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$ (1)

Donde:

$F_{1}$ - Fuerza experimentada por el elefante, medida en newtons.

$F_{2}$ - Fuerza aplicada sobre el plato pequeño, medida en newtons.

$A_{1}$ - Área del plato grande, medida en metros cuadrados.

$A_{2}$ - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

$F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}$

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

$F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g$ (2)

Donde:

$D_{1}$ - Diámetro del plato grande, medido en centímetros.

$D_{2}$ - Diámetro del plato pequeño, medido en centímetros.

$m$ - Masa del elefante, medida en kilogramos.

$g$ - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que $D_{1} = 0.75\,m$ , $D_{2} = 0.13\,m$ , $m = 2900\,kg$ y $g = 9.807\,\frac{m}{s^{2}}$ , entonces la fuerza a aplicar al émbolo pequeño es:

$F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F_{2} = 854.473\,N$

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0

3 years ago

A sample of students that had stuffy or runny noses were blindly given a single Skittles candy to put in their mouth. They were

Korvikt [17]

Answer:

The confidence interval is $0.2857< p < 0.4601$

Step-by-step explanation:

From the question we are told that

The sample size is n = 118

The number that gave the correct answer is k = 44

Generally the sample proportion is mathematically represented as

$\^ p = \frac{44}{118}$

=> $\^ p =0.3729$

Generally given that the confidence level is 95% the level of significance is mathematically represented as

$\alpha = (100 -95) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{p(1 - p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.3729(1 - 0.3729)}{118} }$

=> $E = 0.0872$

Generally 95% confidence interval is mathematically represented as

$\r p -E < p < \r p +E$

=> $0.3729 -0.0872< p < 0.3729 +0.0872$

=> $0.2857< p < 0.4601$

5 0

3 years ago

A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil

erma4kov [3.2K]

Answer:

$\frac{n_p}{n_s}=\frac{1}{1000}$

Step-by-step explanation:

Given voltage of primary coil is $V_p=12V$

And voltage of secondary coil is $V_s=12,000V$

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil $(n_p)$ and secondary coil $(n_s)$ .

Following equation represents the relation between them.

$\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}$

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

$\frac{n_p}{n_s}=\frac{1}{1000}$

5 0

3 years ago

If a desk is 36 inches how many feet is it there are 12 inches in a foot

Maksim231197 [3]

3 feet because 36 divided by 12 is 3

3 0

3 years ago

Read 2 more answers

Help me please geometry class

artcher [175]

Answer:

m∠ADB = 59°

Step-by-step explanation:

I've provided my work which also includes how I check my answers by using the information given! Hope this helps!!! If you have any questions, I can try to help.

6 0

3 years ago