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maxonik [38]
3 years ago
15

What is the value of f(-12) if f(x) = 4x - 12

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

-36

Step-by-step explanation:

Just plug in -12 for x

f(x) = 4 x (-12) -12

-48 - 12 = -36

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Answer:

10

Step-by-step explanation:

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Please help image attached!
Contact [7]

Answer:

The unit circle centered at the origin in the Euclidean plane is defined by the equation:

x^2+y^2=1\\

Given an angle , there is a unique point P on the unit circle at an angle θ from the x-axis, and the x- and y-coordinates of P are:

x=cos \theta \\y = sin \theta

Consequently, from the equation for the unit circle:

cos^2\theta+sin^2\theta=1  

the Pythagorean identity.

5 0
3 years ago
Trudy borrowed $560.00 from a friend and agreed that for several years she would make equal monthly payments to pay only the int
likoan [24]

Answer:

$54.6

Step-by-step explanation:

Amount borrowed = $560

Interest paid in the 12-month period = 6.5% of 560 =$36.4

The amount of interest Trudy pays in 18 months is worked out as

Monthly interest = $36.4/12

Interest payable in 18 months

= ($36.4/12) x 18

= $54.6

5 0
3 years ago
In a certain card game you draw one card off a standard deck of 52 cards. If you draw a spade you get paid $12, if you draw a re
Mariulka [41]

Step-by-step explanation:

In a standard deck of 52 cards, there are 2 red aces, 2 red Queens, and 13 spades.  That leaves 35 cards for everything else.

For the game to be fair, the cost must equal the expected value.  The expected value is the sum of each outcome times its probability.

C = (12) (13/52) + (20) (2/52) + (38) (2/52) + (0) (35/52)

C = 68/13

C ≈ 5.2308

4 0
3 years ago
Diamonds have a density of 3.5 LaTeX: \frac{g}{cm^3}g c m 3. How big is a diamond that has a mass of 0.10 g?
liubo4ka [24]

For this case we have that by definition, the density is given by:

d = \frac {M} {V}

Where:

M: It is the mass of the diamond

V: It is the volume of the diamond

According to the data of the statement we have:

d = 3.5 \frac {g} {cm ^ 3}\\M = 0.10 \ g

So the volume is:

V = \frac {M} {d}\\V = \frac {0.10 \ g} {3.5 \frac {g} {cm ^ 3}}\\V = 0.02857\\V = 0.03 \ cm^3

Thus, the volume of the diamond is approximately 0.03 \ cm ^ 3

Answer:

0.03 \ cm ^ 3

3 0
3 years ago
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