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Mars2501 [29]
3 years ago
11

Solve the following system by any method. -8x-8y=0 and -8x+2y=-20

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

x=2\\y=-2

Step-by-step explanation:

-8x-8y=0

Solve -8x-8y=0 for x

-8x-8y+8y=0+8y

-8x=8y

x=-1y

-8x+2y=-20

Substitute -1y for x

-8(-1y)+2y=-20

8y+2y=-20

10y=-20

y=-2

Substitute -2 for y

x=-1y

x=-1(-2)

x=2

Goryan [66]3 years ago
3 0

<em>X=</em><em>2</em>

<em>y=</em><em>-</em><em>2</em>

please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment....

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Can someone please help me with this question?!? I am so confused and I don't know how to answer it.
lbvjy [14]

9514 1404 393

Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

  a) f(0) = 1

  b) lim x → 0 does not exist

  c) f(2) does not exist

  d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0
2 years ago
Find the midpoint m of the line segment joining the points p (-5,-3) = q and = (-1,-1)
babymother [125]
Hello, hope this makes some sense, the midpoint formula is what’s given in the picture and the rest is just substitution

5 0
1 year ago
Find equations of the spheres with center(1, −1, 6)that touch the following planes.a) xy-planeb) yz-planec) xz-plane
Misha Larkins [42]

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

a)

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

(x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36

b)

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1

c)

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1

Hence , this is the required solution .

4 0
3 years ago
A 30% acid solution was mixed with a 10% acid solution. The result was 600g of a 15% solution. How much of each solution was use
AlexFokin [52]
____________________________________

3 0
3 years ago
How do you solve this equation? <br> 8 - 3 (2m-5)
attashe74 [19]
8 + -3 * 2m + (-3)(-5) = 8 + -6m + 15 = 8 + -6m + 15 = (-6m) + (8 + 15 ) = -6m + 23


so the answer is  -6m + 23
8 0
2 years ago
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