Answer:
6, 2, 2/3, 2/9, 2/27, 2/81
Step-by-step explanation:
The nth term of a geometric progression is expressed as;
Tn = ar^n-1
a is the first term
n is the number of terms
r is the common ratio
Given
a = 6
r = 1/3
when n = 1
T1 = 6(1/3)^1-1
T1 = 6(1/3)^0
T1 = 6
when n = 2
T2= 6(1/3)^2-1
T2= 6(1/3)^1
T2 = 2
when n = 3
T3 = 6(1/3)^3-1
T3= 6(1/3)^2
T3= 6 * 1/9
T3 = 2/3
when n = 4
T4 = 6(1/3)^4-1
T4= 6(1/3)^3
T4= 6 * 1/27
T4 = 2/9
when n = 5
T5 = 6(1/3)^5-1
T5= 6(1/3)^4
T5= 6 * 1/81
T5 = 2/27
when n = 6
T6 = 6(1/3)^6-1
T6= 6(1/3)^5
T6= 6 * 1/243
T6 = 2/81
Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81
12 cubes of 1/4
Simply do 3 ><4=12 so 12 1/r cubes
Answer:
x = 68
Step-by-step explanation:
If you look at the triangle properly, it is a isosceles triangle where two legs are equal to each other.
The answer for x will be:
56 + 56 + x =180
112 + x = 180
x = 68
The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.
- x ≠ 0
- y ≠ 0
- Sign(x) =sign(y)
<h3>
Which points are solutions of the inequality?</h3>
We want to find points of the form (x, y) that are solutions of the inequality:
x*y > 0
Clearly x and y must be different than zero.
So, for example if x = -1, y can be any negative number, for example y= -3
x*y > 0
(-1)*(-3) > 0
3 > 0
This is true.
Now if x = 1, y must be positive. LEt's take y = 103, then:
x*y > 0
1*103 > 0
103 > 0
Then we have 3 conditions:
- x ≠ 0
- y ≠ 0
- Sign(x) =sign(y)
The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.
If you want to learn more about inequalities:
brainly.com/question/25275758
#SPJ1
8*100=20*x
800 =20x
40 =x
40 items are in the basket
