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Aleks [24]
3 years ago
6

For a game, three people are chosen in the first round. Each of those people chooses 3 people in the second round, and so on. Ho

w many people are chosen in the sixth round?
Mathematics
2 answers:
vodka [1.7K]3 years ago
6 0
18 because, 3 in the first round, 6 in the second round, 9 in the third round, 12 in the fourth round, 15 in the fifth round, and 18 on the sixth round.

Hope this helps you :)
leva [86]3 years ago
5 0
Game 1: 3 people are chosen or 3^1
Game2: each chooses 3 , so 3x3=9 or 3^2
.
.
.
Game6: 3^6 or 729
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Lina has 12 coins in her purse. D of them are dimes and the rest are quarters. How many quarters does Lina have? How much money
andrey2020 [161]
D=dimes
q=quarters
if she has 12 coins then
12-d=q she has 12-d quarters
we dont know how much money she has unless we know d.
she could have 12 dimes and 0 quarters or 11 dimes and 1 quarter etc. we need more information to solve.
3 0
3 years ago
Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title="\frac{3}
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The answer would be 14/15

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4 0
3 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

4 0
3 years ago
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