Five consecutive integers are:
n, n+1, n+2, n+3, n+4 the sum of which is:
5n+10=265 subtract 10 from both sides
5n=255, divide both sides by 5
n=51
Our fifth number was n+4 so the fifth number is 55
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
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Ahh! Finally done with this, if you have any doubt just do ask me :)
Answer:
Let us say x is a real number and z = a + ib is complex
|x| > 0
|z| = |a + ib| = square-root (a^2 + b^2)
Step-by-step explanation:
|x| > 0 the absolute value of a real number is a nonnegative real number
The |a + ib| = square-root of the sum of the squares of the real components of the complex number
