102/159 = x/4 Find X

If tan 3x =<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="\sqrt{x}" align="absmiddle"

aliya0001 [1]

Answer:

tan3x=√3

tan3x=tan60,tan(180+60)

3x=60,240

:.x=20,80is your answer.

c=

6 0

3 years ago

What is the surface area of the cylinder to the nearest square inch ?

boyakko [2]

$\bf \textit{surface area of a cylinder}\\\\
S=2\pi r(h+r)\qquad 
\begin{cases}
h=height\\
r=radius
\end{cases}$

looking at the picture above... you do have the radius, is just in the truncated part of the picture... so you have "h" and "r", so just plug them in

4 0

3 years ago

A vegetable garden is in the shape of a parallelogram with the dimensions shown.Parallelogram A B C D is shown. The length of A

olga55 [171]

Answer:

t needs 68 feet to enclose the garden.

Step-by-step explanation:

In this problem, we are to solve the sides of a parallelogram ABCD to know the measurement to enclose a garden.

Take note that a parallelogram has two equal lengths and two equal widths. Let us assume that the parallelogram AB = CD is the length and AD = BC is the width.

Solving the problem

First, let us solve for r using the condition AD = BC

AD = BC

3r + 8 = 2r + 12

Simplify the equation

3r - 2r = 12 - 8

r = 4

Next, let us substitute the value of r to AB, BC, CD, and AD.

For AB:

AB = 4r - 2

AB = 4(4) - 2

AB = 16 - 2 = 14

For BC:

BC = 2r + 12

BC = 2(4) + 12

BC = 8 + 12 = 20

For AD:

AD = 3r + 8

AD = 3(4) + 8

AD = 12 + 8 = 20

For CD:

But AB = CD Therefore, CD = 14

Finally, let us solve the perimeter of the parallelogram

Perimeter = AB + BC + CD + AD

Perimeter = 14 + 20 + 20 + 14

Perimeter = 68 feet

Therefore, the fencing needed to enclose the garden is 68 feet.

To learn more, just click the following links:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2%

Georgia [21]

Answer:

0.98g+ 0.02m= 7.1224 gallons standard mixture

0.96g+ 0.04m= 6.25 gallons break oil

3.92 gallons of gasoline is required for 4 gallons the standard mixture

Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

Gasoline: Motor oil

6 : x

98 : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

0.98g+ 0.02m= 7.1224 gallons standard mixture

For break in oil

Gasoline: Motor oil

6 : x

96 : 4

Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

0.96g+ 0.04m= 6.25 gallons break oil

Part b. For 4 gallons of the "break in" mixture

96% of the 4 gallons of the "break in" mixture is gasoline = 3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

2% of 4 gallons= 0.08 gallons of motor oil.

6 0

3 years ago

100 POINTS HELP ASAP Linear Combination

notka56 [123]

Answer:

1) $x=\dfrac12$

2) $n = -3 \ \ \textsf{and} \ \ m = -4$

3) see below

4) A: 0 = 1

Step-by-step explanation:

Question 1

$15-0.5(4x-2)+4x=17$

$\implies 15-2x+1+4x=17$

$\implies 2x+16=17$

$\implies 2x=1$

$\implies x=\dfrac12$

Question 2

$\textsf{rearrange} \ n=m+1 :$

$\implies -m=-n+1$

$\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\$

$\implies0=n+3$

$\implies n=-3$

$\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:$

$\implies m=-3-1$

$\implies m=-4$

Question 3

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

Question 4

$3j=k$

$k=3j+1$

$\textsf{rearrange} \ 3j=k :$

$\implies -k=-3j$

$\textsf{add equations}\ -k=-3j \ \ \textsf{and}\ \ k=3j+1:$

$\implies 0=1$

Solution = A

6 0

2 years ago