Answer:
The initial value is 60 m and the slope is 40 m/min.
Step-by-step explanation:
The graph shows the depth, y, in meters, of a shark from the surface of an ocean for a certain amount of time, x, in minutes.
See the graph attached.
Part A : If we consider two right triangles one Δ ABD and Δ BCE, where D(2,100) and E(1,60) points.
Now, those two triangles are similar and hence the slope of line segment AB will be .
Again, the slope of the line segment BC will be
Hence, and the slope of AB and BC are the same. (Answer)
Part B : From the graph, it is clear that the initial value of the graph is 60 m and it represents that initial position of the shark i.e. at t = 0 min, the shark was at a depth of 60 m from the water surface.
The slope of the graph is 40 means the rate of change of distance from the Ocean surface of the shark with respect to time in minutes will be 40 m per min. (Answer)
<em><u>There you go, I hope its right!</u></em>
Answer:
C
Step-by-step explanation:
1st year-> 30000
2nd year-> 31800
3rd year ->33708
4th year->35730.48
5th year -> 37874.3088
37874.3088+35730.48+33708+31800+30000= 169112.7888
≈ 169113
Answer:
−
3
(
1
+
4
)
=
3
3
Step-by-step explanation:
Answer:
Step-by-step explanation:
If two lines are parallel then they will have the same slope. So all you need to do is find the slope of the line that joins the two given points. You can use the slope formula . You can also graph the two points and use rise over run.
Answer:
The answer is below
Step-by-step explanation:
To find the maximum amount of cargo the truck can carry, we need to find the volume of the truck.
Volume = length × width × height.
Firstly 1 feet (1') = 12 inches (12"),
For the extra ledge that sticks out, the height = 7'8" = 7.667 feet, the width = 16'9" - 14'3" = 16.75 - 14.25 = 2.5 feet, the length = 2'7" = 2.583 feet
Volume of extra ledge = length × width × height = 2.583 × 2.5 × 7.667 = 49.5 feet³
For the truck, the height = 7'8" = 7.667 feet, the length = 14'3" = 14.25 feet, the width = 6'6" = 6.5 feet
Volume of truck = length × width × height = 14.25 × 6.5 × 7.667 = 710.16 feet³
The maximum volume = volume of extra ledge + volume of truck = 49.5 + 710.16 = 759.66 feet³