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3 years ago

What is two hundred sixty-five thousandths in decimal form

1 answer:

4 0

.265

Decimals are ALWAYS tenths, hundredths, then thousandths.

So in this case the 2 will be in the tenths place
the 6 will be in the hundredths place
the 5 will be in the thousandths place.

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Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B645%20%5Ctimes%20645%7D%20" id="TexForm

Sergio039 [100]

$208012.5$

Step-by-step explanation:

$\sqrt{645 \times 645}$

$= \sqrt{416025}$

$= 208012.5$

3 0

3 years ago

Read 2 more answers

Solve 2x² + 3x - 2 > 0

katrin2010 [14]

Answer:

(-∞,-2)∪( $\frac{1}{2}$ ,∞)

Step-by-step explanation:

i think it's right

8 0

3 years ago

PLEASE PLEASE HELP ME OUT AND EXPLAIN

Shalnov [3]

$4 more each time. You can tell that Raphael is growing at a rate of 6 every week (40 to 46 to 52 to 58) and Jessica is Growing at $10 each week because it is what is in front of the x. Raphael's formula would look like y=6x+40 because they started at 40 and grew by 6 every week.

3 0

3 years ago

The equation p(t) = 1.e represents a

zvonat [6]

Answer:

(b), (d) and (e)

Step-by-step explanation:

Given

$p(t) = 1 * e^t$

See attachment for $y = p(t)$

Required

Select true statements from the given options

(a) $\ln(30)$ = days the bacteria reaches 30000

We have:

$p(t) = 1 * e^t$

In this case:

$t = \ln(30)$ and $p(t) = 30000$

So, we have:

$30000 = 1 * e^{\ln(30)}$

$30000 = e^{\ln(30)}$

Using a calculator, we have:

$e^{\ln(30)} = 30$

So:

$30000 = 30$

The above equation is false.

(a) is not true

(b) The graph shows that $\ln(20) \approx 3$

We have:

$p(t) = 1 * e^t$

Let t = 3

So;

$p(3) = 1 * e^3$

From the graph, $p(3) = 20$

So:

$20 = 1 * e^3$

$20 = e^3$

Take natural logarithm of both sides

$\ln(20) = \ln(e^3)$

This gives:

$\ln(20) = 3$

(b) is true

(c) $\ln(t) = y$ is the logarithm form of $y = e^t$

We have:

$y = e^t$

Take natural logarithm of both sides

$\ln(y) = \ln(e^t)$

This gives:

$\ln(y) = t$

$\ln(y) = t$ $\ne$ $\ln(t) = y$

(c) is false

(d) $e^4 > 50$ and $\ln(50) < 4$

From the graph, we have:

$e^4 = 54$ --- rough readings

This implies that:

$e^4 > 50$ is true

Because $54 > 50$

Take natural logarithm of both sides

$\ln(54) > \ln(50)$

Rewrite as:

$\ln(50) < \ln(54)$

We have:

$e^4 = 54$

Take natural logarithm of both sides

$\ln(e^4) = \ln(54)$

$4 = \ln(54)$

$\ln(54) = 4$

Substitute $\ln(54) = 4$ in $\ln(50) < \ln(54)$

$\ln(50) < 4$

(d) is true

(e) The graph shows that $10 \approx \ln(2.3)$

We have:

$p(t) = 1 * e^t$

Let t = 2.3

So;

$p(2.3) = 1 * e^{2.3}$

From the graph,

$p(2.3) = 10$ ---- rough readings

So:

$10 = 1 * e^{2.3}$

$10 = e^{2.3}$

Take natural logarithm of both sides

$\ln(10) = \ln(e^{2.3})$

This gives:

$\ln(10) = 2.3$

(e) is true

4 0

3 years ago

Suponhamos que temos x casos confirmados de coronavírus e y casos suspeitos. A - Se triplicar os casos confirmados e cair a meta

aleksandr82 [10.1K]

Answer:

[3x + (y/2)]

Step-by-step explanation:

English Translation

Suppose we have x confirmed cases of coronavirus and y suspected cases. A - If the confirmed cases triple and half of the suspects fall, we will have the following expression to represent the total number of cases:

Solution

Number of confirmed cases = x

Number of suspected cases = y

Number of confirmed cases triples and becomes 3x

Half of the suspected cases fall and becomes (y/2)

Total number of cases then becomes

[3x + (y/2)]

In Portugese/Em português

Número de casos confirmados = x

Número de casos suspeitos = y

O número de casos confirmados triplica e se torna 3x

Metade dos casos suspeitos cai e se torna (y / 2)

O número total de casos passa a ser

[3x + (y / 2)]

Hope this Helps!!!

Espero que isto ajude!!!

8 0

3 years ago