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3 years ago

PLEASE PLEASE HELP ME OUT AND EXPLAIN

Mathematics

1 answer:

Shalnov [3]3 years ago

3 0

$4 more each time. You can tell that Raphael is growing at a rate of 6 every week (40 to 46 to 52 to 58) and Jessica is Growing at $10 each week because it is what is in front of the x. Raphael's formula would look like y=6x+40 because they started at 40 and grew by 6 every week.

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Inequality #1<br> o ²5 n-3 (n-6)

Afina-wow [57]

Let's simplify step-by-step.

o25n−3(n−6)

Distribute:

=o25n+(−3)(n)+(−3)(−6)

=no25+−3n+18

Answer:

=no25−3n+18

(Pls mark as brainliest) (:

7 0

3 years ago

Leah and Carl share a 12-ounce box of cereal. By the end of the week, Leah has eaten

Anton [14]

Answer: Use Fractions and Multiplication.

Step-by-step explanation:

To start, you need to find 1/6 of 12. The easiest way to do this is to multiply 12/1 by 1/6. The answer is 12/6, which simplifies to 2. Then, you do the same for 2/3: 12/1*2/3=24/3, which simplifies to 8. You then add the results to figure out how much has been eaten. 8+2=10

7 0

4 years ago

60731903239__8DEE49CD-5BBC-40E2-A8F5-59B32FE3879C.jpeg

Sergio [31]

Answer:No

Step-by-step explanation:

4 0

3 years ago

Maria, a biologist, is observing the growth pattern of a virus. She starts with 100 of the virus that grows at a rate of 10% per

Leni [432]

<h3>Answer: 985</h3>

=============================================

Work Shown:

A = amount after t hours

P = initial amount = 100

r = growth rate in decimal form = 0.10

t = number of hours = 24

--------

A = P*(1+r)^t

A = 100(1+0.10)^24

A = 100*(1.10)^24

A = 100*9.84973267580762

A = 984.973267580762

A = 985

5 0

3 years ago

Read 2 more answers

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$