You meant to say x^2 - 49 and the second binomial is x^2 - 16.
x^2 - 49 = (x - 7) (x + 7).
Set each factor to 0 and solve for x individually.
x - 7 = 0
x = 7
x + 7 = 0
x = -7
Do the same for x^2 - 16.
Here is the set up:
x^2 - 16 = (x - 4) (x + 4).
Take it from here.
Answer:
f(x)=6
Step-by-step explanation:
3(-4)/2+(-4)
-12/-2
f(x)=6
Okay, here we have this:
Considering the provided information and grades, we are going to calculate the requested GPA, so we obtain the following:
Then we will substitute in the following formula:

Then:

Finally we obtain that the student's GPA for that term is approximately 3.06.