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3 years ago

What is 765903 rounded to the nearest ten thousand

Mathematics

1 answer:

earnstyle [38]3 years ago

4 0

That would be 770,000 Answer

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What percentage of the data values represented on a box plot falls between the minimum value and the lower quartile?

Butoxors [25]

Answer:

first 25%

Step-by-step explanation:

A quartile is a quarter, so the first 25% falls between the minimum and lower quartile

4 0

3 years ago

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Your family eats at Pizza Hut for dinner. The pizza is $12.99. An order of bread sticks is $5.99. Four drinks were purchased for

Anton [14]

Answer:

$22.87

Step-by-step explanation:

12.99+5.99+2.20=21.18

22.18x.08=1.6944

1.69+22.18=22.87

7 0

2 years ago

Please help!posted picture of question

ale4655 [162]

We have the following arithmetic series:
4, 13, 22, 31, 40
The common difference is given by:
13-4 = 9
22-13 = 9
31-22 = 9
40-31 = 9
Since it is an arithmetic series, the difference is constant.
Answer:
The common difference is:
9
option 4

7 0

2 years ago

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

What is the answer to <br> 2x + 3y = 13 <br> x = 2

stira [4]

$\bf2x+3y=13$

Plug in x = 2:

$\bf2(2)+3y=13$

Multiply:

$\bf4+3y=13$

Subtract 4 to both sides:

$\bf3y=9$

Divide 3 to both sides:

$\bf~y=3$

So our solution is $\boxed{\bf(2,3)}$

7 0

3 years ago

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