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slavikrds [6]
3 years ago
8

A rectangle an area of 52 square feet .the length is 9 feet longer than the width. What equation could use to represent this ?

Mathematics
1 answer:
TEA [102]3 years ago
5 0

Answer:

idk

Step-by-step explanation:

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2 years ago
Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
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\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

x^3=x\cdot x^2, and x(x^2+2x+1)=x^3+2x^2+x. Subtracting this from the numerator gives a remainder of

(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39

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\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}

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