Answer: 2-6p-6q-18
Step-by-step explanation:
Answer:a)
a) 68%
b) 44%
Step-by-step explanation: a) (51+51)/150 × 100 = 102/150 × 100
= 17/25 × 100
= 68%
Answer:
5
Step-by-step explanation:
Use PEMDAS to complete the problem
PE doesn't matter, there's not parentheses or exponents
MD=Multiplication and Division. Do 3*6=9, now your problem looks like 9-4
AS=Addition and Subtraction. 9-4=5
Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649