<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
-32
Step-by-step explanation:
10–{22–[(−9)+(−11)]}
Work inside out
10–{22–[(-20)]}
Subtracting a negative is adding
10–{22+20}
10 - 42
-32
Answer:
x=9
Step-by-step explanation:
Step 1: Simplify by both sides of the equation.
80-3x=53
80+-3x=53
-3x+80=53
Step 2: Subtract 80 from both sides.
-3x+80-80=53-80
-3x=-27
Step 3: Divide by both sides by 3.
-3x/-3 = -27/-3
x=9
Answer:
x = -1 or x = -7
Step-by-step explanation:
y = (x + 4)^2 - 9
To find x-intercept, set y = 0
=> (x + 4)^2 - 9 = 0
=> ( x + 1)( x + 7) = 0
=> x = -1 or x = -7
