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chubhunter [2.5K]
3 years ago
6

Warren picked 3/4 of a pound of strawberries. That afternoon, Warrens

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

she ate 6 ounces

Step-by-step explanation:one pound is 16 ounces 3\4 of a pound is 12 ounces half of 12 is 6 ounces

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ira [324]

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Step-by-step explanation:7 ÷4= 4 + 3 ÷ 4 = 30 ÷4 = 2.85

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Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
What is the slope-intercept form for the
stealth61 [152]
Y = 3/5x + b
3 = 3/5(-1) + b
3 = -3/5 + b, b = 3 3/5
Y = 3/5x + 3 3/5
7 0
2 years ago
Read 2 more answers
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