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valentina_108 [34]
3 years ago
14

Rewrite the expression 14m-(5+8m) without parentheses

Mathematics
2 answers:
JulijaS [17]3 years ago
5 0

Answer:

14m-5-8m

Step-by-step explanation:

Triss [41]3 years ago
4 0

Answer: 6m-5

Step-by-step explanation:

First, apply the distributive property and get rid of the parentheses. That will give 14m-5-8m. Now, combine like terms. And that will give the answer 6m-5.

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3x = 2x + 12<br> What is the answer to this equation?
Strike441 [17]

Answer:

x=12

Step-by-step explanation:

3x=2x+12

-2x from each side

x=12

4 0
3 years ago
Read 2 more answers
The diameter of a circle is 1034 inches.
Murrr4er [49]

Answer:

517

Step-by-step explanation:

The radius of a circle is just half of the diameter (1/2d = r)

1034/2 = 517

7 0
2 years ago
Use factoring to solve <br> 3x^2-11x-6=0
Zielflug [23.3K]

Answer:

x = -0.62 and x = 4.29

These values are approximations !

Step-by-step explanation:

You can not use Factoring to solve this equation. Perhaps you did not use the exact notation as in the original question?

Anyway, to solve it, you can still use the ABC formula.

3x²-11x-6=0

a = 3

b =-11

c = -6

x = [11 + √{121 -4(3 *-6)} ]/ 2*3

x = [11 + √{121 -4(-24)} ]/ 6

x = [11 + √{121 + 96} ]/ 6

x = [11 + √{217} ]/ 6

x = 4.29 This is an approximation !

x = [11 - √{121 -4(3 *-6)} ]/ 2*3

x = [11 - √{121 -4(-24)} ]/ 6

x = [11 - √{121 + 96} ]/ 6

x = [11 - √{217} ]/ 6

x = -0.62 This is an approximation !

extra: see the graph.

4 0
3 years ago
Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?
Savatey [412]

Answer:

Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?

Question 2. What is the area of Rectangle ABCD in terms of y?

Question 3. If the perimeter of the rectangle is 70. What is it’s area?

Question 4. What are the length and width of the rectangle?

6 0
3 years ago
In a certain sequence of all positive terms, {a1, a2, a3, …} each term equals the previous term times a constant factor. If (a1)
andriy [413]

Let k be the constant factor between terms, so that

a_2=ka_1

a_3=ka_2=k^2a_1

and so on, with

a_n=ka_{n-1}=\cdots=k^{n-1}a_1

(notice how the exponent and the subscript add to n)

Then

a_5=k^4a_1

so if

a_1a_5=900

then

k^4{a_1}^2=900\implies k^4=\dfrac{900}{{a_1}^2}=\left(\dfrac{30}{a_1}\right)^2\implies k^2=\dfrac{30}{a_1}

Now,

a_3=k^2a_1=\dfrac{30a_1}{a_1}=30

so the third term in the sequence is 30.

7 0
3 years ago
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