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stepan [7]
3 years ago
12

Please help solve one of them

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer: im not sure

Step-by-step explanation:

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Can you answer this math homework? Please!
luda_lava [24]

Answer: (3.5,-2)

Step-by-step explanation:

To solve this problem, all we have to do is plug in y=-2 into either equations from step one to find the coordinate. To make sure we have the right x-coordinate, let's plug in y for both equations.

4x-7y=28        [plug in y=-2]

4x-7(-2)=28    [multiply]

4x+14=28       [subtract both sides by 14]

4x=14              [divide both sides by 4]

x=3.5

------------------------------------------------------------------------------------------------------------

6x-5y=31        [plug in y=-2]

6x-5(-2)=31    [multiply]

6x+10=31       [subtract both sides by 10]

6x=21             [divide both sides by 6]

x=3.5

Now, we know the solution to the system is (3.5,-2).

3 0
3 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST<br> -SEE ATTACHMENT-
yuradex [85]

ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

The coefficients are :

1, 5, 10,10, 5,1

Because of the negative sign, the expansion will alternate sign.

(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

We now put y=5 into the expansion to get,

(x - 5) ^{5}  =  {x}^{5}  - 5 {x}^{4} (5) + 10 {x}^{3} ( {5}^{2})  - 10 {x}^{2}  ({5})^{3}  + 5x( {5})^{4}  - {5}^{5}

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

3 0
4 years ago
Read 2 more answers
Tegan needs to make 686868 more snow blocks to finish building an igloo. Write an equation for the number of blocks Tegan still
Keith_Richards [23]

Answer:

We are given:

No: of blocks Tegan still needs to make = m.

No: of blocks Tegan has completed = c

Total No:of more snow blocks need to make = 68 .

Total number of more snow blocks need to make = Total number of blocks -  The number of blocks Tegan has completed.

m = 68 - c.

Therefore, the equation for the number of blocks Tegan still needs to make, m, when she has completed c blocks is

m = 68 - c.

For example.

Suppose if c = 10, it means Tegan still needs to make 68-10 = 58 block.

8 0
3 years ago
If rent to go charges you $30 for 300 miles what is the unit rate per 1 mile
lesantik [10]

Answer:

$10

Step-by-step explanation:

300 divided by 30 is 10

3 0
3 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
3 years ago
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