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victus00 [196]
3 years ago
9

Will need to flip my sign in order to solve this? -3x≥ 12 yes or no

Mathematics
1 answer:
lisov135 [29]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

the value of x has to be positive

-12≥ 3x

-4≥ x

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Which equation represents the graphed line? linear graph y=5
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y=-2x+5

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O is the centre of the circle and ABC and EDC are tangents to the circle
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3 years ago
Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).
saul85 [17]

Answer:

P(x,y) = (0,\frac{11}{5})

Step-by-step explanation:

Given

A = (-2,1)

B = (3,4)

m:n = 2:3

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:

P(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

Where

(x_1,y_1) = (-2,1)

(x_2,y_2) = (3,4)

m:n = 2:3

This gives:

P(x,y) = (\frac{2 * 3 + 3 * -2}{2 + 3},\frac{2 * 4 + 3 * 1}{2 + 3})

P(x,y) = (\frac{6 - 6}{5},\frac{8 + 3}{5})

P(x,y) = (\frac{0}{5},\frac{11}{5})

P(x,y) = (0,\frac{11}{5})

5 0
3 years ago
Which number is rational?<br> GIVING OUT BRAINLIEST!!
mojhsa [17]

Answer:

The 4th option.

Step-by-step explanation:

Rational numbers are numbers which can be expressed as a fraction. Irrational numbers are numbers which can't be expressed as a fraction. Square root 16 is a perfect square so it is a rational number.

4 0
2 years ago
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Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.
SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

8 0
2 years ago
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