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Novosadov [1.4K]
3 years ago
6

In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of t

he cross section be x and formed a right triangle with hypotenuse r, as shown below.
The cross-sectional area of the shaded circle is πx2. Using the Pythagorean theorem for the right triangle, we get x2 + b2 = r2. Now solve for x2 and substitute it into the area expression.

What is the result?

π(r2 – b2)
π(r2 + b2)
π(b2 – r2)
2π(b2 + r2)
Mathematics
2 answers:
Pavel [41]3 years ago
8 0

Answer:

A π(r2 – b2)

Just did the assignment.

IceJOKER [234]3 years ago
5 0

Answer:

Answer A 3.14(r2-b2)

Step-by-step explanation:

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