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4 years ago

N the following Earliest Start Time (EST) graph, assume each unit of time is an hour.

Mathematics

1 answer:

lesantik [10]4 years ago

5 0

Answer:

Step-by-step explanation:

It takes 4 hours to do task E using the route: start ⇒B⇒E

It will take 6 hours to do task E if using route : start ⇒C ⇒E

Taking the shortest route, it will take 4 hours

You can apply the critical path method to identify the shortest route possible. First , specify the activity and look for their dependencies.Using the activity diagram, establish the activity completion time.Finally, identify the critical path using the best case estimate.

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I’ll mark brainlest

Alla [95]

Answer:

48,841,380.8

Step-by-step:

find 12% of 14,365,112= 1,723,813.44

then find 1,723,813.44×20= 34,476,268.8

then 34,476,268.8+14,365,112=48,841,380.8

3 0

3 years ago

Read 2 more answers

What exponential function is best fit for the data table?

Sedaia [141]

F(x) = 3(2)^(x − 2)<span> + 4</span>

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3 years ago

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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that $a = 10400, b = 15400$

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

$P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32$

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

$P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72$

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

6 0

3 years ago

PLEASE HELP!! what is the equation for the parabolic function that goes through the points (-3, 67) (-1, 1) and has a stretch fa

barxatty [35]

Answer:

$f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}$

Step-by-step explanation:

So, we need to find the equation of a parabolic function that goes through the points (-3,67) and (-1,1) and has a stretch factor of 9.

In other words, we want to find a quadratic with a vertical stretch of 9 that goes through the points (-3,67) and (-1,1).

To do so, we first need to write some equations. Let's use the vertex form of the quadratic equation. The vertex form is:

$f(x)=a(x-h)^2+k$

Where a is the leading coefficient and (h,k) is the vertex.

Since a is the leading coefficient, it's also our stretch factor. Thus, let a equal 9.

Also, we have two points. We can interpret them as functions. In other words, (-3,67) means that f(-3) equals 67 and (-1,1) means that f(-1) equals 1. Write the two equations:

$f(x)=a(x-h)^2+k\\f(-3)=67=9((-3)-h)^2+k$

And:

$f(x)=a(x-h)^2+k\\f(-1)=1=9((-1)-h)^2+k$

Now, we essentially have a system of equations. Thus, to find the original equation, we just need to solve for the vertex. To do so, first isolate the k term in the second equation:

$1=9(-1-h)^2+k\\k=1-9(-1-h)^2$