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2 years ago

Why isn't 10 a perfect square

1 answer:

3 0

Because there is no number that when multiplied by itself that could equal to 10 (ex: 16 is a perfect square because 4 and 4 multiplied together equals 16; 4 and 4 are the same number)

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The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( , ). The coordinates of the point that is

AURORKA [14]

Answer:

Reflection across the x-axis: (-4,2)

Reflection across the y-axis: (4,-2)

Step-by-step explanation:

Going based off of what I see, a reflection across the x axis changes "y" & the same rule applies to the y axis.

It should be an L shape.

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3 years ago

How many square feet of cedar are needed to line the four walls of a closet that is a square prism 5 1/2 ft on each edge

Alex777 [14]

22 square feet because there is 5 1/2 on each wall

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2 years ago

Write an equation in the slope-intercept form of the line.

nata0808 [166]

Answer: Y= 1/-2x + 2

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2 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

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Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

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Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

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2 years ago

Ivy is trying to manage the money she spends on lunch. Between eating out and buying groceries for bagged lunches, she wants to

Jlenok [28]

choice one is correct.

8 0

2 years ago

Read 2 more answers