Answer:
Explanation:
You can build a two-way relative frequency table to represent the data:
These are the columns and rows:
Car No car Total
Boys
Girl
Total
Fill the table
- <em>30% of the children at the school are boys</em>
Car No car Total
Boys 30%
Girl
Total
- <em>60% of the boys at the school arrive by car</em>
That is 60% of 30% = 0.6 × 30% = 18%
Car No car Total
Boys 18% 30%
Girls
Total
By difference you can fill the cell of Boy and No car: 30% - 18% = 12%
Car No car Total
Boy 18% 12% 30%
Girl
Total
Also, you know that the grand total is 100%
Car No car Total
Boy 18% 12% 30%
Girl
Total 100%
By difference you fill the total of Girls: 100% - 30% = 70%
Car No car Total
Boy 18% 12% 30%
Girl 70%
Total 100%
- <em>80% of the girls at the school arrive by car</em>
That is 80% of 70% = 0.8 × 70% = 56%
Car No car Total
Boy 18% 12% 30%
Girl 56% 70%
Total 100%
Now you can finish filling in the whole table calculating the differences:
Car No car Total
Boy 18% 12% 30%
Girl 56% 14% 70%
Total 74% 26% 100%
Having the table completed you can find any relevant probability.
The probability that a child chosen at random from the school arrives by car is the total of the column Car: 74%.
That is because that column represents the percent of boys and girls that that arrive by car: 18% of the boys, 56% of the girls, and 74% of all the the children.
Answer:
Measure of exterior angle ABD = 136°
Step-by-step explanation:
Given:
measure of ∠A = (2x + 2)°
measure of ∠C = (x + 4)°
measure of ∠B = x°
Find:
Measure of exterior angle ABD
Computation:
Using angles sum property
∠A + ∠B + ∠C = 180°
So,
(2x + 2) + (x + 4) + x = 180
4x + 6 = 180
4x = 176
x = 44
So,
measure of ∠B = x°
measure of ∠B = 44°
Measure of exterior angle ABD = 180 - measure of ∠B
Measure of exterior angle ABD = 180 - 44
Measure of exterior angle ABD = 136°
Answer:
The Susana swam the fastest.
Step-by-step explanation:
<u>Speed</u> : It is defined as the distance traveled per unit time.
<u>Formula used</u> : 
First we have to determine speed of the following persons.
<u>For Tawni :</u>
Distance = 50 m
Time = 40.8 s
1.225 m/s which is the speed of Tawni.
--
<u>For Pepita :</u>
Distance = 100 m
Time = 60.2 s
1.661 m/s which is the speed of Pepita
--
<u>For Susana :</u>
Distance = 200 m
Time = 112.4 s
1.779 m/s which is the speed of Susana
From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.
Thus, Susana swam the fastest.
Answer is <u>6|x+2|+2</u>
Please check the attached image of answer to clear the doubt.
<em>By </em><em>Benjemin</em><em> </em>☺️