Answer:
demon,harold,val
Explanation:
as it say that damon is on the left nut not necessary to next to val .harlord was also to the left of varl so on the most right side varl was there and also there was one person who was on the right of harold so harold have one person on the left other on the right harold was in center varl was on right most side and damon was on left most side
Answer:
place your cursor or highlight the text where you wish to insert a bulleted list. Under the [Home] tab in the “Paragraph” section, click the [Bullets] drop-down menu. Choose a bullet style or select "Bullets and Numbering” to create a customized bullet style.
Answer:
"Disk Striping" would be the right choice.
Explanation:
- Disk stripping has become a methodology where certain numerous small external drives consist of a single massive disk. This same classification turns huge information into single blocks but instead disperses them over numerous different storage media.
- Disk stripping retail outlets instead of every data unit through a single place and doesn't provide disk failure safeguards.
Answer:
3 bits
Explanation:
Given a 4- way set associative cache that has 64 blocks of 16 words.
Therefore, the number of sets cache has:
![\frac{64}{4} = 16](https://tex.z-dn.net/?f=%5Cfrac%7B64%7D%7B4%7D%20%3D%2016%20)
Now,
Cache data size is 16kB
The number of cache blocks can be calculated as:
![16kB/16 = 1024 bytes/16 byte\times 16 = 256 cache blocks](https://tex.z-dn.net/?f=16kB%2F16%20%3D%201024%20bytes%2F16%20byte%5Ctimes%2016%20%3D%20256%20cache%20blocks)
Now,
Total sets = ![\frac{cache blocks}{associative sets}](https://tex.z-dn.net/?f=%5Cfrac%7Bcache%20blocks%7D%7Bassociative%20sets%7D)
Total sets = ![\frac{256}{4} = 64](https://tex.z-dn.net/?f=%5Cfrac%7B256%7D%7B4%7D%20%3D%2064)
Now,
![2^{n} = 64](https://tex.z-dn.net/?f=2%5E%7Bn%7D%20%3D%2064)
n = 6
For 15 bit address for the architecture, the bits in tag field is given by:
15 - (6 + 6) = 3 bits
Thus the tag field will have 3 bits