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Anastasy [175]
3 years ago
6

Factor 2x+4 (Please and Thanks)

Mathematics
1 answer:
lara31 [8.8K]3 years ago
6 0
2 is common factor
2x=2(x)
4=2(2)

ab+ac=a(b+c)
2(x)+2(2)=2(x+2)
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There are 28 students in Ms. Annand’s class. 25% got an A on their last math quiz. How many students did not receive an A on the
Luden [163]

Answer:

21 students

Step-by-step explanation:

25% of 28 is 7 28-7=21

8 0
3 years ago
camille rides the bus to work. to get downtown,she can ride any bus number between 11 and 34, that can be divided evenly by 3, a
almond37 [142]

Answer:

12, 18, 24, 30

Step-by-step explanation:

List the numbers between 11 and 34 that can be evenly divided by 3:

12, 15, 18, 21, 24, 27, 30, 33

Then eliminate the odd numbers, obtaining:

12, 18, 24, 30

These are the four busses that Camille could ride to work.

7 0
3 years ago
Dane started running at half past three in the afternoon. He stopped running at ten minutes after four. How long did Dane run?
Tatiana [17]
He ran for 40 minutes!
4 0
3 years ago
Read 2 more answers
How do you round money to the nearest cent?Like for ex.:$2.15 to the nearest cent
Digiron [165]


To round money to the nearest cent you would see in the ones place what that number is and if it is at or higher than 5 it would round up to 2.20               

Did that help any I hope so:) if not tell me I will have another strategy

7 0
3 years ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
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