^ 3 sqrt 750 + ^ 3 sqrt 2058 - ^ 3 sqrt 48
Rewriting the expression we have
^ 3 sqrt (6 * x ^ 3) + ^ 3 sqrt (6 * y ^ 3) - ^ 3 sqrt (6 * z ^ 3)
That is, we have the following equations:
6 * x ^ 3 = 750
6 * y ^ 3 = 2058
6 * z ^ 3 = 48
Clearing x, y and z we have:
x = 5
y = 7
z = 2
Then, rewriting the expression
x (^ 3 sqrt (6)) + y (^ 3 sqrt (6)) - z (^ 3 sqrt (6))
Substituting the values
5 (^ 3 sqrt (6)) + 7 (^ 3 sqrt (6 *)) - 2 (^ 3 sqrt (6))
10 (^ 3 sqrt (6))
answer
the simple form of the expression is
D) 10 ^ 3 sqrt 6
Angle g would be congruent/equal to itself because of verticals angles theorem. i hope that helped a bit
Answer:
i. Estimated number of free throws of the best player = 0.85 * 40
ii. 34 free throws
Step-by-step explanation:
Percentage of free throws made by the best player = 85%
Percentage of free throws made by the second best player = 75%
Percentage of free throws made by the third best player = 70%
Therefore, for 40 attempts;
i. Estimated number of free throws made by the best player = 85% x 40
= 0.85 x 40
= 34
ii. Estimated number of free throws made by the second best player = 75%x 40
= 0.75 x 40
= 30
iii. Estimated number of free throws made by the third best player = 70% x 40
= 0.70 x 40
= 28
Thus, the equation that gives the estimated number of free throws is 0.85 * 40.
The best player will make about 34 free throws.
Answer:
The answer is below
Step-by-step explanation:
a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packaging box was 40 cm longer than its width and the height 12 cm, volume was at most 4800 cm3. Suppose the length of the new packaging box is still 40cm longer than its width and the height is 12cm, what mathematical statement would represent the volume of the new packaging box?
Solution:
Let the width of the box be x cm.
The length of the box is 40 cm longer than the width, therefore the length of the box = x + 40
The height of the box = 12 cm
The volume of the box can be gotten from the formula:
Volume = length × width × height
Substituting:
Volume = (x + 40) × (x) × 12
Volume = 12x(x + 40)
Therefore the volume of the new box is 12x(x + 40)
