Question

Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west. What was the time of her trip? (There are 60 seconds in 1 minute. ) 18. 5 minutes 20. 4 minutes 2 hours 3 hours.

Answer 1

The time taken for her trip is 3 hours.

Given that

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

We have to determine

What was the time of her trip?

According to the question

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.

The formula to calculate the time for her trip is;

$\rm Speed = \dfrac{ Distance}{Time}\\ \\ Time = \dfrac{Distance}{Speed}$

• Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

• If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

$\rm\ Time = \dfrac{Distance}{Speed}\\\\ Time = \dfrac{45000}{270}\\ \\ Time =166.7$

Converting minutes into hours,

$\rm Hours = \dfrac{Minute}{60}\\ \\ Hours = \dfrac{166.7}{60}\\ \\ Hours = 2.77 \\ \\ = 3\ hours$

Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818