All categories

3 years ago

lonnie bought 6 pieces of ribbon. Each ribbon was 2 and 3/4 yards long. How much ribbon did Lonnie buy in all

Mathematics

1 answer:

ollegr [7]3 years ago

7 0

Answer:

14.04

Step-by-step explanation:

you mupltiy

You might be interested in

f(x)=2x. If g(x) is a vertical stretch, compression, and or reflection of f(x) followed by a, what is the equation of g(x)?

Montano1993 [528]

The function g(x) is g(x)= (3x)^2

<h3>How to solve for g(x)?</h3>

The complete question is in the image

From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

So, we have:

g(x)= (3x)^2

Hence, the function g(x) is g(x)= (3x)^2

Read more about function transformation at:

brainly.com/question/10222182

#SPJ1

7 0

2 years ago

Which line of best fit accurately represents the given scatter plot?

Fofino [41]

The third one down
Because the best line of fit is a line that goes between the plotted points and it HAS to be a straight line and most of the points close to the line

8 0

2 years ago

Please help math questions put number with answers please

natita [175]

Answer:

See below for answers

Step-by-step explanation:

Problem 1

$\frac{1}{sin\theta}=2cos\theta\: ; \: 0\leq\theta < 2\pi\\\\1=2sin\theta cos\theta\\\\1=sin2\theta\\\\\frac{\pi}{2}+2\pi n=2\theta\\ \\\frac{\pi}{4}+\pi n=\theta\\ \\\theta=\bigr\{\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\bigr\}$

Therefore, the second option is correct.

Problem 2

$cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)$

$0=sinx\\\\x=\pi n\\\\x=0,\pi$

$0=2sinx+1\\\\-1=2sinx\\\\-\frac{1}{2}=sinx\\ \\x=\frac{7\pi}{6}+2\pi n,\frac{11\pi}{6}+2\pi n\\\\x=\frac{7\pi}{6},\frac{11\pi}{6}$

Therefore, the solution set is $x=\bigr\{0,\pi,\frac{7\pi}{6},\frac{11\pi}{6}\bigr\}$ , making the second option correct.

Problem 3

$2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0$

$cosx=0\\\\x=\frac{\pi}{2}+\pi n\\ \\x=90^\circ+180n^\circ\\\\x=90^\circ,270^\circ$

$2cosx+1=0\\\\2cosx=-1\\\\cosx=-\frac{1}{2}\\\\x=\frac{2\pi}{3}+2\pi n,\frac{4\pi}{3}+2\pi n\\ \\x=120^\circ+360n^\circ,240^\circ+360n^\circ\\\\x=120^\circ,240^\circ$

Therefore, the solution set is $x=\bigr\{90^\circ,120^\circ,240^\circ,270^\circ\bigr\}$ , making the fourth option correct

7 0

2 years ago

Please help with #2 please

disa [49]

Answer:

167.5

Step-by-step explanation:

For surface area all you have to do is multiply each number by one of the other numbers x2.

7 0

4 years ago

9x^2 y^2 and 5x^2 y^3 look for the greatest common factor

Aneli [31]

Answer:

x^2 y^2

Step-by-step explanation:

9x^2y^2/x^2y^2=9

5x^2y^2/x^2y^2=5

since 9 and 5 have no common factors except 1, x^2 y^2

mark as brainliest plz

8 0

3 years ago