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What is the lateral area of a right cylinder if the radius of the base is 12 mm and the altitude of the cylinder is 5 times the

lakkis [162]

The lateral area of a cylinder is given by:
Area=πrl+2πr^2
radius,r=12 mm
length,l=5*12=60mm
therefore the lateral area will be:
Area=π*12*60
Area=2,261.95 mm^2
The area of the bases will be:
A=2*π*12^2=904.78 mm^s
The lateral area will be:
2,261.95+904.78
=3,166.73
=3167 mm^2

5 0

3 years ago

Teague is participating in a 50K run to raise money for a charity. He has already raised $102 and will receive $1.40 for each ki

Volgvan

He has to run 45 kilometers

3 0

3 years ago

Solve this

sesenic [268]

A sandwich store charges a delivery fee to bring lunch to an office.

Delivery cost - D

Meatball sandwich cost - M

One office pays $40.50 for 5 meatball sandwiches.

40.50 = 5M + D

Another office pays $66.50 for 9 meat ball sandwiches

66.50 = 9M + D

A. How much does each meatball sandwich add to the cost of delivery?

D = 40.50 - 5M = 66.50 - 9M

40.50 - 5M = 66.50 - 9M

9M - 5M = 66.50 - 40.50

4M = 26.00

M = 6.50

B. What is the delivery fee

D = 40.50 - 5M = 40.50 - 5(6.50) = 40.50 - 32.50 = 8.00

Check

66.50 = 9M + D = 9(6.50) + 8 = 58.50 + 8.00 = 66.50

3 0

3 years ago

A piece of string measures 2 16/20. Which of the following is equivalent to the length of the string in meters?

Ivenika [448]

Answer:

H: 2.8

Step-by-step explanation:

first divide 16 by 20 then you get a decimal.

then you add the decimal answer to the whole number (2)

7 0

4 years ago

Read 2 more answers

An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t

solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation = $\sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}$

Suppose,

X X - Xbar $(X - Xbar)^{2}$

3 3 - 6 = -3 -3 * -3 = 9

5 5 - 6 = -1 -1 * -1 = 1

10 10 - 6 = 4 4 * 4 = 16

Mean of above data, Xbar = $\frac{3+ 5+10}{3}$ = 6

Standard Deviation of data = $\sqrt{\frac{26}{3-1} }$ = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

X X - Xbar $(X - Xbar)^{2}$

3*2 = 6 6 - 12 = -6 -6 * -6 = 36

5*2 = 10 10 - 12 = -2 -2 * -2 = 4

10*2 =20 20 - 12 = 8 8 * 8 = 64

Mean of new data, Xbar = $\frac{6+ 10+20}{3}$ = 12

Standard Deviation of new data = $\sqrt{\frac{104}{3-1} }$ = 7.2111

Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as

3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.

8 0

4 years ago