Answer:
We have to find point that partition line segment AB with end points (-5,3) (-1,-5) in ratio 1:3
Assume (-5,3) as ( a,b)
Assume (-1,-5) as (c,d)
Assume ratio 1:3 as m:n
Step-by-step explanation:
Remember this formula
Partition point =( mc + na)/m+ n , ( md+ nb)/m+n
=[ (1)(-1)+ 3(-5)]/1+3, ( 1(-5) + 3(3))/1+3
= -1 -15)/4,( -5 + 9)/4
= -16/4, 4/4
= -4, 1
2)
perpendicular lines because the slopes are opposite reciprocals
~iln~
( /^ω^)/♪♪
Answer:
(4a - 9)(4a + 9)
Step-by-step explanation:
Every value in the equation has a square root
The square root of 16 is 4
The square root of a^2 is a
The square root of 81 is 9.
To factor you split the equation by the square roots. For 81, since the original value is negative, one of the roots must be negative so when you multiply it back out to the original, it stays the same.
You can check your answer this way too.
(4a -9)(4a + 9)
= 16a^2 + 36a - 36a - 81
= 16a^2 - 81
I hope this helps!
Answer:
120th caller
Step-by-step explanation:
120 is the common number by 40 and 30. trust me on this I'm really good at this subject in math.
