The concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.
<h3>What is pH value?</h3>
The pH value shows that how much a solution is acidic or basic. The range of the pH value lies between the 0-14.
The pH value can be calculated with the following formula.
![\rm pH=log[H^{+}]](https://tex.z-dn.net/?f=%5Crm%20pH%3Dlog%5BH%5E%7B%2B%7D%5D)
Here, [H⁺] is the molar hydrogen ion concentration.
The pH of lemon juice at 298 K is found to be 2. 32. Put this value of pH in the above formula as,
![\rm 2.32=log[H^{+}]\\\ [H^{+}]=4.79\times10^{-3} \rm \; M](https://tex.z-dn.net/?f=%5Crm%202.32%3Dlog%5BH%5E%7B%2B%7D%5D%5C%5C%5C%20%5BH%5E%7B%2B%7D%5D%3D4.79%5Ctimes10%5E%7B-3%7D%20%5Crm%20%5C%3B%20M)
Hence, the concentration of ions in the solution of lemon juice whose pH value is 2.32 is 4.79×10⁻³ M.
Learn more about the pH value here;
brainly.com/question/940314
To solve for variable h flip the equation. You get: 12gh=f. After, divide both sides by 12 to get your answer: h=f/12g
Answer: I think c but im not too sure
Step-by-step explanation;
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
