Answer:
The values of
so that
have vertical asymptotes are
,
,
,
,
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of
so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is
. Then, the vertical asymptotes associated with function cosecant are located in the values of
of the form:
, 
In other words, the values of
so that
have vertical asymptotes are
,
,
,
,
.
You didnt list any graph?? Can you add it please :)
Step-by-step explanation:
x/3-2/5=2x/15-3x
5x-6=2x-9
5x-2x=-9+6
3x=-3
3x/3=-3/3
x=-1
Answer:
y = 3/4 + 7
Step-by-step explanation:
you must put the equation into the form of y = mx + b
add 6x to both sides and put it in front of the 56
8y = 6x + 56
y must be by itself by x does not so we divide everything by 8
y = 6/8x + 7
we must simplify the fraction 6/8
y = 3/4x + 7