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3 years ago

Find inequality x^4-13x^2 36>0

1 answer:

7 0

x<−21.633308 or x>21.633308
This is the answer ;D

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Can you solve (4k-9)(2k-2 in algebra 1 put it in explanation on how you got your answer

Oksana_A [137]

(4k-9)(2k-2)

First you're going to want to multiply the 4k by the 2k & the -2. Then you're going to want to multiply the -9 by the 2k and the -2.

(4k-9)(2k-2)

4k * 2k = 8k^2

4k * -2 = -8k

-9 * 2k = -18k

-9 * -2 = +18

Since we have like terms (-8k and -18k) put those together.

-8k + -18k = -26k.

Now you're going to want to put all of these together in an equation.

You want to order the numbers from the highest number of exponents (8k^2) to the lowest.

8k^2 - 26k + 18

So the correct answer is 8k^2 - 26k + 18.

3 0

3 years ago

Karen needs to make a total of 60 deliveries this week. So far she has completed 33 of them What percentage of her total deliver

Luden [163]

Answer:

55%

Step-by-step explanation:

(33/60) * 100

leave a comment if u need further explanation

6 0

2 years ago

Write an equation of the line that is parallel to 2x + 4y = 6 and passes through the point (6, 4).

notsponge [240]

Answer:

Step-by-step explanation:

Here's a completely valid trick for finding the equation of this new line:

Start with the given 2x + 4y = 6. Replace that '6' with 'C.' We need to find C. To do this, replace x with 6 and y with 4 and calculate C:

2(6) + 4(4) = C, or 12 + 16 = C. Thus, C = 28, and the desired equation is

2x + 4y = 28, or (in simplified form) x + 2y = 14

3 0

3 years ago

In this 2x3 grid, each lattice point is one unit away from its nearest neighbors. A total of 14 isosceles triangles(but not righ

pickupchik [31]

The area of a shape is the amount of space it can occupy.

The number of isosceles triangle in the grid is: $\mathbf{\frac{2x^2}{u^2}}$

The dimension of the grid is given as:

$\mathbf{Dimension = x\ by\ x}$

Calculate the area

$\mathbf{A_1 = x\ \times \ x}$

$\mathbf{A_1 = x^2}$

The area of each isosceles triangle is given as:

$\mathbf{A_2 = \frac 12u^2}$

The number (n) of the triangle in an x-by-x grid is:

$\mathbf{n = A_1 \div A_2}$

So, we have:

$\mathbf{n = x^2 \div \frac 12u^2}$

Express as products

$\mathbf{n = x^2 \times \frac{2}{u^2}}$

$\mathbf{n = \frac{2x^2}{u^2}}$

Hence, the number of isosceles triangle in the grid is: $\mathbf{\frac{2x^2}{u^2}}$